php - 将下拉列表中的多个输入保存到数据库

Question

我是 yii 的新手，我无法将多个选定的数据存储到数据库中。 我的数据库“product”“seller”和“productseller”中有三个表，具有多对多关系。 product 表包含 pro_name 和 pro_id 字段，seller 表包含 sel_id 和 sel_name 字段，productseller 表包含 pro_id 和 sel_id 字段。 我正在做的是从下拉列表中选择卖家名称和相关的多个产品，然后将它们存储在 productseller 表中。

我的观点:

    <div class="row">
                <?php echo $form->labelEx($model,'Select Seller'); ?>
                <?php echo $form->dropDownList($model,'sel_id', 
            CHtml::listData(Seller::model()->findAll(), 'sel_id', 'sel_name')); ?>
                <?php echo $form->error($model,'sel_id'); ?>
</div>

<div class="row">
            <?php echo $form->labelEx($model,'Choose Products'); ?>
            <?php //echo $form->textField($model,'maincat_id'); ?>
            <?php echo $form->dropDownList($model, 'pro_id', 
CHtml::listData(Product::model()->findAll(), 'pro_id', 'pro_name'),
            array('multiple'=>'multiple', 'size'=>5)); ?>
            <?php echo $form->error($model,'maincat_id'); ?>
    </div>

我的卖家 Controller

$model = new ProductSeller;     
            $this->render('insertItems', array('model'=>$model));
            if(isset($_POST['ProductSeller']))
            {
                    $model->attributes=$_POST['ProductSeller'];
                    if($model->save())

                            $this->redirect(array('view','id'=>$model-   >sel_id));
                            $this->redirect(array('view','id'=>$model->pro_id));

            }

卖家模式

public function relations()
    {
            // NOTE: you may need to adjust the relation name and the related
            // class name for the relations automatically generated below.
            return array(
                    'productSellers' => array(self::HAS_MANY, 'ProductSeller', 'sel_id'),
            );
    }

产品型号

  public function relations()
    {
            // NOTE: you may need to adjust the relation name and the related
            // class name for the relations automatically generated below.
            return array(
                    'productSellers' => array(self::HAS_MANY, 'ProductSeller', 'pro_id'),
            );
    }

ProductSeller 模型

public function relations()
    {
            // NOTE: you may need to adjust the relation name and the related
            // class name for the relations automatically generated below.
            return array(
                    'pro' => array(self::BELONGS_TO, 'Product', 'pro_id'),
                    'sel' => array(self::BELONGS_TO, 'Seller', 'sel_id'),
            );
    }

将 pro_id 和 sel_id 保存到数据库应该遵循什么步骤？ 谢谢 0

Answer 1

只需进行最少的更改，您的操作应如下所示:

$model = new ProductSeller;
if(isset($_POST['ProductSeller'])){
  $is_valid = true;
  $list = array();
  foreach( $_POST['ProductSeller']['pro_id'] as $pro_id ) {
    $list[ $pro_id ] = new ProductSeller;
    $list[ $pro_id ]->setAttributes(array(
      'sel_id' => $_POST['ProductSeller']['sel_id'],
      'pro_id' => $pro_id,
    ));
    $is_valid = $list[ $pro_id ]->validate() && $is_valid;
  }

  if ( $is_valid ) {
    foreach( $list as $m ) {
      $m->save(false);
    ));
    $this->redirect(/*...*/);
  }
}
$this->render('insertItems',array('model'=>$model));