我正在尝试使用在线 MySQL 服务器发送我的 SQLite 数据,但无济于事。自然而然,我跑去谷歌,幸运地找到了this。 .显然它应该可以工作并且确实可以工作,但我没有在我的服务器上接收到数据。
我知道有人问过这个问题here和 here ,但我无法使用给出的建议对其进行修补。
这是我试过的。这就是我使用 GSON 将 SQLite 数据转换为 JSON 的方式:
public String composeJSONfromSQLite() {
ArrayList<HashMap<String, String>> offlineList;
offlineList = new ArrayList<HashMap<String, String>>();
String selectQuery = "SELECT * FROM offlineTable ";
SQLiteDatabase database = this.getWritableDatabase();
Cursor cursor = database.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
HashMap<String, String> map = new HashMap<String, String>();
map.put("zip", cursor.getString(1));
map.put("phone", cursor.getString(2));
map.put("uid", cursor.getString(3));
offlineList.add(map);
} while (cursor.moveToNext());
}
database.close();
Gson gson = new GsonBuilder().create();
//Use GSON to serialize Array List to JSON
return gson.toJson(offlineList);
}
这就是我将它发送到我的服务器的方式:
public void syncSQLiteMySQLDB() {
AsyncHttpClient client = new AsyncHttpClient();
RequestParams params = new RequestParams();
params.put("offline",loadCheckoutDB.composeJSONfromSQLite());
Log.d("offline data log", loadCheckoutDB.composeJSONfromSQLite());
client.addHeader("session_id", getapikey());
client.addHeader("Content-Type", "application/json");
client.post("http://example.com/offline/api", params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {
String s = new String(responseBody);
Log.d("response to sync", s);
try {
JSONObject obj = new JSONObject(s);
if (obj.getBoolean("success")) {
String success = obj.getString("message");
//Toast.makeText(getApplicationContext(), success, Toast.LENGTH_LONG).show();
} else {
String failure = obj.getString("message");
//Toast.makeText(getApplicationContext(), failure, Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
}
}
@Override
public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
// Toast.makeText(getApplicationContext(), "Failed to sync with server", Toast.LENGTH_LONG).show();
Log.d("sqlite sync error", String.valueOf(error));
progbar.setVisibility(View.INVISIBLE);
}
});
}
当我从 Android 记录 JASON 的样子时,我得到这种格式:
[{
"zip": "325,
"phone": "78291849",
"uid": "14538177211"
}]
但是在我的服务器上我得到的仍然是一个空数组。我做错了什么?
我的请求格式应该是这样的:
{
"offline":[
{
"zip": "325,
"phone": "78291849",
"uid": "14538177211"
}
]
}
这是我收到请求的方式:
public function massData()
// offline sync
{
$input = Input::all();
return $input;
最佳答案
将您的列表添加到 map ,其中键为 offline
并为该列表赋值:
public String composeJSONfromSQLite() {
ArrayList<HashMap<String, String>> offlineList;
offlineList = new ArrayList<HashMap<String, String>>();
String selectQuery = "SELECT * FROM offlineTable ";
SQLiteDatabase database = this.getWritableDatabase();
Cursor cursor = database.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
HashMap<String, String> map = new HashMap<String, String>();
map.put("zip", cursor.getString(1));
map.put("phone", cursor.getString(2));
map.put("uid", cursor.getString(3));
offlineList.add(map);
} while (cursor.moveToNext());
}
HashMap<String, ArrayList<HashMap<String, String>>> offlineMap = new HashMap<String, ArrayList<HashMap<String, String>>>();
offlineMap.put("offline", offlineList);
database.close();
Gson gson = new GsonBuilder().create();
//Use GSON to serialize Array List to JSON
return gson.toJson(offlineMap);
}
关于java - 如何将 SQLite 数据从 Android 发送到 MySQL 服务器?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35067507/