php - 无法使用 PHP、MySQL 和 Volley 进行 Android 登录

Question

我正在尝试借助 volley 为 Android 应用程序设置注册和登录 Activity 。我已经能够设置注册页面了 我的登录 Activity 有问题
因为电子邮件和密码与数据库不匹配。我正在使用在线服务器 我的登录 Activity 有一个代码

        package com.gjs.tablepay;

 import android.app.ProgressDialog;
 import android.content.Intent;
 import android.support.v7.app.AppCompatActivity;
 import android.os.Bundle;
 import android.util.Log;
 import android.view.View;
 import android.widget.Button;
 import android.widget.EditText;
 import android.widget.TextView;
import android.widget.Toast;

import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import com.android.volley.toolbox.Volley;

import org.json.JSONArray;
import org.json.JSONObject;

import java.lang.reflect.Type;
import java.util.ArrayList;
import java.util.List;


public class LoginActivity extends AppCompatActivity {

EditText etxtloginemail,etxtloginpassword;
TextView txtRegister,txtforgotpass;
Button btnlogin;
  PersonBean personbean;

// Is the Request to the Server
StringRequest stringRequest;

// Executes the Request
RequestQueue requestQueue;
ArrayList<PersonBean> personList;
ProgressDialog pd;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_login);

    etxtloginemail=(EditText)findViewById(R.id.editTextloginemail);
    etxtloginpassword=(EditText)findViewById(R.id.editTextloginpassword);
    btnlogin=(Button)findViewById(R.id.buttonLogin);
    txtRegister=(TextView)findViewById(R.id.textViewregister);
    txtforgotpass=(TextView)findViewById(R.id.textViewforgotpass);

    personbean = new PersonBean();

    // Initialize Volley's Request Queue
    requestQueue = Volley.newRequestQueue(this);
    pd = new ProgressDialog(this);

    txtRegister.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            startActivity(new Intent(LoginActivity.this,RegistrationActivity.class));
        }
    });
    txtforgotpass.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

                startActivity(new Intent(LoginActivity.this,ForgotpassActivity.class));
        }
    });
    btnlogin.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            init();
        }
    });}

void retrievePerson(){

    pd.show();
    stringRequest = new StringRequest(Request.Method.POST, Util.RETRIEVE_URL,

            // success
            new Response.Listener<String>() {
                @Override
                public void onResponse(String s) {
                    pd.dismiss();
                        Toast.makeText(LoginActivity.this,"yo",Toast.LENGTH_LONG).show();

                        if(s.equalsIgnoreCase("success")){
                            Toast.makeText(LoginActivity.this,"yo",Toast.LENGTH_LONG).show();
                            startActivity(new Intent(LoginActivity.this,HomeActivity.class));

                        }else{
                            pd.dismiss();
                            Toast.makeText(LoginActivity.this,"No Person Found",Toast.LENGTH_LONG).show();
                        }

                    }

            },

            // failure
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError volleyError) {
                   // Toast.makeText(AllPersonsActivity.this,"Some Volley Error", Toast.LENGTH_LONG).show();
                    Log.i("AllPersonsActivity", volleyError.toString());
                    Log.i("AllPersonsActivity",volleyError.getMessage());
                }
            }
    );

    // Execute the StringRequest
    requestQueue.add(stringRequest);

}
    void init(){
          personbean.setEmail(etxtloginemail.getText().toString().trim());
        personbean.setPassword(etxtloginpassword.getText().toString().trim());
        if(personbean.validateLoginPerson()){

            if(Util.isNetworkConnected(this)){

                retrievePerson();

            }else{
                Toast.makeText(this,"Please check your connectivity",Toast.LENGTH_LONG).show();
            }

        }else{
            Toast.makeText(this,"Please Enter Details First",Toast.LENGTH_LONG).show();
        }
    }

这是我的 login.php

 <?php
$email=$_POST['email'];
$password=$_POST['password'];
include("dbconfig.php");

  $user = @mysql_query("select uid from users where email='$email' and password='$password'");  

 $row = mysql_fetch_array($user,MYSQL_ASSOC);
      $active = $row['active'];
$count = @mysql_num_rows($user);

$response =array();

 if($count==1){
    $response['success']=1;
    $response['message']="Records Retrieved sucessfully";
 }else{
    $response['success']=0;
    $response['message']="Retrieval Failure";
 }
 echo json_encode($response);
?>

Answer 1

在您的代码中，您缺少指定变量的 getParams()。 它应该看起来像这样:

StringRequest request = new StringRequest(Request.Method.POST, insertURL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.d("=======", "DEVICE ID SENT");
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e("=======", "DEVICE ID ERROR");
        }
    }) {
        @Override
        protected Map<String, String> getParams() throws AuthFailureError {
            Map<String, String> parameters = new HashMap<>();
            parameters.put("id",userID);
            parameters.put("deviceId", token);
            return parameters;
        }
    };