我正在尝试获取表单中选定值的键(主键),因此我可以将键添加到连接表中。我将表单从下拉列表更改为自动完成。但不知道如何使用 jquery 进行映射。
这是我的自动完成 php
<?php
if (isset($_POST['type']) && $_POST['type'] == 'faculty_id') {
$type = $_POST['type'];
$name = $_POST['name_startsWith'];
$nameID = $_POST['nameID'];
$query = "SELECT FirstName, LastName, FacultyId FROM Test.Faculty where UPPER(FirstName) LIKE '" . strtoupper($name) . "%'";
$result = mysqli_query($con, $query);
$data = array();
while ($row = mysqli_fetch_assoc($result)) {
$name = $row['FirstName'] . ' ' . $row['LastName'];
$nameID = $row['FacultyId'];
array_push($data, $name);
}
mysqli_close($con);
echo json_encode($data);
exit;
}
?>
这是表单和 jQuery 页面
<form action="Form.php" method="post">
<input type='text' id="faculty_id" placeholder="Instructor" name="faculty_id" value='' />
<input type="submit" value="submit" name="submit" />
</form>
<script type="text/javascript">
$('#faculty_id').autocomplete({
source: function (request, response) {
$.ajax({
url: 'Form.php',
dataType: "json",
method: 'post',
data: {
name_startsWith: request.term,
nameID: request.term,
type: 'faculty_id'
},
success: function (data) {
response($.map(data, function (item) {
console.log(item);
//var code = item.split("|");
return {
label: item,
value: item,
data: item
}
}));
}
});
},
autoFocus: true,
minLength: 1,
});
</script>
和 php 插入查询
<?php
if (isset($_POST)) {
$faculty_id = $_POST['faculty_id'];
try {
$stat = $db->prepare("Insert into ATCTest.Schedule
(Faculty )
VALUE (':faculty_id' )");
$stat->bindParam(":faculty_id", $faculty_id);
if ($stat->execute()) {
echo "<h5>Faculty-js: " . $faculty_id . "</h5>";
} else {
echo "Problem!!!";
}
} catch (PDOException $e) {
echo $e->getMessage();
}
}
最佳答案
我将使用 PDO,因为我发现它比 MySQLi 更容易使用。
- 使用适当的请求方法。如果您要获取某些东西,请使用 GET 而不是 POST。如果您要添加或更新,请使用 POST。
让我们重写您的自动完成脚本以使用 PDO:
if (isset($_GET['type']) && $_GET['type'] == 'faculty_id') {
// this will hold your response that gets sent back
$data = null;
$name = trim($_GET['name']);
try {
// because you are passed untrusted data, use prepared statement
$sth = $db->prepare("
SELECT FirstName, LastName, FacultyId
FROM Test.Faculty
WHERE UPPER(FirstName) LIKE UPPER(?)
");
$sth->execute(array($name . '%'));
// set the results (array of objects) as your JSON response
$data['faculties'] = $sth->fetchAll(PDO::FETCH_OBJ);
} catch(PDOException $e){
echo $e->getMessage();
}
// send the results i.e. response
header('Content-Type: application/json');
echo json_encode($data);
exit;
}
我以前从未使用过自动完成插件,但我会根据我看到的其他答案来尝试一下。
$('#faculty_id').autocomplete({ source: function (request, response) { // short syntax for .ajax() using GET method that expects a JSON response $.getJSON('Form.php', { type: 'faculty_id', name: request.term }, function (data) { // data.faculties (your AJAX script's response) should now be an array of objects console.log(data.faculties); response($.map(data.faculties, function (faculty) { console.log(faculty); return { label: faculty.FirstName + ' ' + faculty.LastName, value: faculty.FacultyId } })); }); }, autoFocus: true, minLength: 1, });
最后,当你插入
// check if form was POSTed if ($_SERVER['REQUEST_METHOD'] === 'POST') { $faculty_id = $_POST['faculty_id']; try { // VALUES not VALUE // don't wrap your placeholders with quotes in your prepared statement // simplified $sth = $db->prepare("INSERT INTO ATCTest.Schedule(Faculty) VALUES(?)"); // simplified way to bind parameters $sth->execute(array($faculty_id)); // use rowCount() not execute() to determine if the operation was successful or not if ($sth->rowCount()){ echo "<h5>Faculty-js: $faculty_id</h5>"; } else { echo "Problem!!!"; } } catch (PDOException $e) { echo $e->getMessage(); } }
关于javascript - php/jQuery 获取所选值的主键,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40810297/