php - 根据codeigniter中的外键从两个表中获取json编码数据

Question

我有一个问题要问你，但我还没有找到解决方案，所以我有 2 个表:

类别:

id  category

1   BBA
2   BSCS
3   BEE

子类别:

id  category_id sub_category_name
1       1           Accountant
2       1           Manager
3       1           Sales
4       2           Data Adminsitrator
5       2           Web Developer
6       3           Airline Pilot
7       3           Airport Security Screener
8       3           Aircraft Mechanic

我想从第一个表中加入两个表我想获得类别和类别下我想要所有子类别

我的 Controller 看起来像这样:

public function getVehicles()
    {
        $result = $this->crud_m->getUserVehicles($data,'vehicle');
        return $this->output->set_output(json_encode(array(     
                'status' => 'OK',
                'statusCode' => '402',
                'response' => array(   
                        'description' => 'Details',
                        'category'=> $result
                )
            )));

        }

我的模型是这样的:

    public function getUserVehicles($data)
        {   
            $this->db->select('*');
            $this->db->from('categories');                      
            $this->db->join('sub_category','sub_category.category_id=categories.id');
            $this->db->group_by('categories.id');
            $query = $this->db->get();
            $result = $query->result();
            if(empty($result)){     
                return '401';
                }
            else{

                return $result; 
            }
        }

我的输出现在是这样的:

{
  "status": "OK",
  "statusCode": "402",
  "response": {
    "description": "Details",
    "category": [
      {
        "id": "1",
        "category": "BBA",
        "category_id": "1",
        "sub_category_name": "Accountant"
      },
      {
        "id": "4",
        "category": "BSCS",
        "category_id": "2",
        "sub_category_name": "Data Adminsitrator"
      },
      {
        "id": "6",
        "category": "BEE",
        "category_id": "3",
        "sub_category_name": "Airline Pilot"
      }
    ]
  }
}

我需要的是这样的:

[
  {
    "categoryId": "1",
    "category": "BBA",
    "subCategory": [
      {
        "subCategoryId": "1",
        "subCategoryName": "Accountant"

      },
      {
        "subCategoryId": "2",
        "subCategoryName": "Manager"

      },
      {
        "subCategoryId": "3",
        "subCategoryName": "Sales"

      }
    ]
  },
  {
    "categoryId": "2",
    "category": "BSCS",
    "subCategory": [
      {
        "subCategoryId": "4",
        "subCategoryName": "Data Adminsitrator"

      },
      {
        "subCategoryId": "5",
        "subCategoryName": "Web developer"

      }
    ]
  }
]

Answer 1

你可以使用下面的代码来获取你喜欢的数据。

    public function getUserVehicles($data)
    {   
        $categories = array();
        $this->db->select('*');
        $this->db->from('categories');                      
        $query = $this->db->get();
        $result = $query->result();
        foreach($result as $r){
            $r['subCategory'] = $this->getSubCategory($r['id']);
            array_push($categories, $r);
        }
        if(empty($result)){     
            return '401';
        }else{
            return $categories; 
        }
    }


        public function getSubCategory($cat)
    {   
        $this->db->select('*');
        $this->db->from('sub_category');      
        $this->db->where('id', $cat);
        $query = $this->db->get();
        $result = $query->result();
        return $result; 
    }