php - 在 fat-free 框架中处理 'Duplicate-entry error'

Question

表中插入重复条目时如何处理错误？ 我尝试了以下方法，但它不起作用。

function leaveBalanceRecord($f3)
{
    $sql = 
    "
    INSERT 
    INTO users_leave_balance (user_id, period, leave_type, leave_balance, rollable_till_date)
    VALUES (134, '2017-01', 1, 10.00, NULL)";
    $results = $this->db->exec($sql);
    if(!$results)
    {
        return 'Duplicate Entries';
    }
    return $results;
}

如果出现此错误，如何处理错误并更新记录？ 任何帮助表示赞赏。谢谢。

Answer 1

针对您的情况，我看到了两种解决方案:

1) 利用 MySQL REPLACE INTO 语法:

$sql='REPLACE INTO users_leave_balance etc.';
$this->db->exec($sql);

来自docs :

REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.

2)捕获PDO异常:

$sql='INSERT INTO users_leave_balance etc.';
try {
  $this->db->exec($sql);
} catch (\PDOException $e) {
  $err=$e->errorInfo;
  if ($err[0]==23000) {
    // duplicate key: do something
  } else {
    // any other error
  }
}

参见 this answer有关如何启用 PDO 异常的详细信息。