php-sql语法错误

Question

我正在尝试将表单数据插入到我的数据库中的一个表中。要插入的数据是姓名、电子邮件、当前日期和用户兴趣。 这是代码。

if (isset($_POST['name'])) {
   $name = $_POST['name'];
   $email = $_POST['email'];
   $intrests = $_POST['intrests'];
   $default_intrests = array("mob","pcs","scm","oth");
   $interests = "";
   if (count($intrests) == 0) {
      $interests = implode(",", $default_intrests);
   }
   else {
          $interests = implode(",", $intrests);
   }

   $sqll="insert into subscriptions (name,email,subdate,intrests) values ($name,$email,CURRENT_DATE, $interests)";
   $insert = mysqli_query($link, $sqll);
   if (!$insert) {
      echo mysqli_error($link);
   }
}

在提交表单时，显示以下错误:

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'dsa,asdf@qwer.com,CURRENT_DATE, mob)' at line 1

Answer 1

将 ' 添加到值中，因为其中一些是 string

 $sqll="insert into subscriptions (name,email,subdate,intrests)
     values ('$name','$email',CURRENT_DATE, '$interests')";

事实上，直接将参数写入sql是个坏主意，最好使用prepared-statements。这样做并避免SQL Injection