好的,我有这个问题
select ss.system_step_id, ss.step_number, cd.name, ssp.system_step_product_id, p.cost, ssp.class_id from system_step ss
join system as s on s.system_id=ss.system_id
join category_description as cd on cd.category_id=ss.sub_category_id
join system_step_product as ssp on ss.system_step_id=ssp.system_step_id
join product as p on p.product_id=ssp.product_id where s.system_id = 41
order by ss.step_number, ssp.class_id;
which yields this result
7 1 Screens 808 115.0000 1
7 1 Screens 809 381.9000 2
7 1 Screens 810 441.9000 3
8 2 Printers 811 112.3200 1
8 2 Printers 812 201.0400 2
8 2 Printers 813 202.8700 3
9 3 Cash Drawers 814 135.7000 1
9 3 Cash Drawers 815 86.5400 2
9 3 Cash Drawers 816 135.7000 3
有没有办法把它变成像这样的三个元素的 php 数组
Array
(
[0] => Array
(
[name] => "Screens"
[standard_product] => Array ([id] => 808, [price] => '115.0000')
[business_product] => Array ([id] => 809, [price] => '381.9000')
[premium_product] => Array ([id] => 810, [price] => '441.9000')
)
[1] => Array
(
[name] => "Printers"
[standard_product] => Array ([id] => 811, [price] => '112.3200')
[business_product] => Array ([id] => 812, [price] => '201.0400')
[premium_product] => Array ([id] => 813, [price] => '202.8700')
)
[2] => Array
(
[name] => "Cash Drawers"
[standard_product] => Array ([id] => 814, [price] => '135.7000')
[business_product] => Array ([id] => 815, [price] => '86.5400')
[premium_product] => Array ([id] => 816, [price] => '135.7000')
)
)
$sql = "select ss.system_step_id, ss.step_number, cd.name, ssp.system_step_product_id, p.cost, ssp.class_id, pd.name as product_name, pd.description from system_step ss join system as s on s.system_id=ss.system_id join category_description as cd on cd.category_id=ss.sub_category_id join system_step_product as ssp on ss.system_step_id=ssp.system_step_id join product as p on p.product_id=ssp.product_id join product_description as pd on pd.product_id=p.product_id where s.system_id = {$system['system_id']} order by ss.step_number, ssp.class_id;";
$result = mysql_query($sql);
$steps = array();
while($row_r = mysql_fetch_assoc($result)){
$steps[] = $row_r;
}
所以步骤是包含 9 个元素的完整数组
如您所见,唯一需要注意的是 class_id 1 是 standard_product class_id 2 是 business_product,class_id 3 是 premium_product
最佳答案
您可以在获取 SQL 结果时填充一个多维数组,或者拆分成多个 SQL 命令,从而构建您的数组(首先获取名称,而不是具有每个名称值的产品)。
我不知道您更喜欢哪个,但是由于您有一个大型连接拆分,就代码的可读性而言,SQL 可能不是最差的。性能影响可能会有所不同。
关于php - 我如何以正确的格式获取这些数据?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5889777/