我有一个从数据库获取“分支”的代码。每个公司可以有多个“分支机构”。
唯一的问题是,那是行不通的。你们能弄清楚出了什么问题吗?
$getbranches = "SELECT * FROM branches ORDER BY naam ASC";
$querygetbranches = mysql_query($getbranches);
while($rijbranche = mysql_fetch_assoc($querygetbranches))
{
echo "<tr>";
echo "<td width='400'>";
echo $rijbranche['naam'];
echo "</td>";
echo "<td>";
$get2 = "SELECT * FROM bedrijf_branche WHERE bedrijf_id = '$id'";
$query2 = mysql_query($get2);
while ($rij20 = mysql_fetch_assoc($query2))
{
$branche_id = $rij20['branche_id'];
}
if($branche_id == $rijbranche['id_branche']){
?>
<input type="checkbox" name="branche[]" value="<?php echo $rijbranche['id_branche']; ?>" CHECKED></input>
<?php
}
else
{
?>
<input type="checkbox" name="branche[]" value="<?php echo $rijbranche['id_branche']; ?>"></input>
<?php
}
echo "</td>";
}
最佳答案
尝试以下代码
<?php
$id = $_GET['id'];
// Output BRANCHES
$getbranches = "SELECT * FROM branches ORDER BY naam ASC";
$querygetbranches = mysql_query($getbranches);
while ($rijbranche = mysql_fetch_array($querygetbranches)) {
echo ' <tr>' . "\n";
echo ' <td width="400">' . $rijbranche['naam'] . '</td>' . "\n";
// Output CHECKBOX
$get2 = mysql_query("SELECT * FROM bedrijf_branche WHERE bedrijf_id = '" . $id . "' AND branche_id = '" . $rijbranche['id_branche'] . "'");
$rij20 = mysql_fetch_array($get2);
$branche_id = $rij20['branche_id'];
if ($branche_id == $rijbranche['id_branche']) {
$checkbox = '<input type="checkbox" name="branche[]" value="' . $rijbranche['id_branche'] . '" checked="checked" />';
}
else {
$checkbox = '<input type="checkbox" name="branche[]" value="' . $rijbranche['id_branche'] . '" />';
}
echo ' <td>' . $checkbox . '</td>' . "\n";
echo ' </tr>' . "\n";
}
?>
发现我在上面的代码中修复了几个错误。
- 您正在关闭
<input>
字段不正确 - 你的第二个
while()
循环是不必要的,因为应该只返回一行 - 您必须添加
branche_id
到你的第二个 mysql_query! - 不要关闭并重新打开您的
<?php ?>
当您只需添加echo
时,为每个 HTML 行添加标签
关于php - 根据数据库中的值选中复选框,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9300889/