我正在处理一个非常复杂的查询,让我尝试向您解释一下。这是我的 MySQL 数据库中的表:
学生表
--- `students` ---
student_id first_name last_name current_status status_change_date
------------ ------------ ----------- ---------------- --------------------
1 John Doe Active NULL
2 Jane Doe Retread 2012-02-01
students_have_courses 表
--- `students_have_courses` ---
students_student_id courses_course_id s_date e_date int_date
--------------------- ------------------- ---------- ---------- -----------
1 1 2012-01-01 2012-01-04 2012-01-05
1 2 2012-01-05 NULL NULL
2 1 2012-01-10 2012-01-11 NULL
students_have_Optional_courses 表
--- `students_have_optional_courses` ---
students_student_id optional_courses_opcourse_id s_date e_date
--------------------- ------------------------------ ---------- ----------
1 1 2012-01-02 2012-01-03
1 1 2012-01-06 NULL
1 5 2012-01-07 NULL
这是我到目前为止的查询
SELECT
`students_and_courses`.student_id,
`students_and_courses`.first_name,
`students_and_courses`.last_name,
`students_and_courses`.courses_course_id,
`students_and_courses`.s_date,
`students_and_courses`.e_date,
`students_and_courses`.int_date,
`students_have_optional_courses`.optional_courses_opcourse_id,
`students_have_optional_courses`.s_date,
`students_have_optional_courses`.e_date
FROM (
SELECT
`c_s_a_s`.student_id,
`c_s_a_s`.first_name,
`c_s_a_s`.last_name,
`c_s_a_s`.courses_course_id,
`c_s_a_s`.s_date,
`c_s_a_s`.e_date,
`c_s_a_s`.int_date
FROM (
SELECT
`students`.student_id,
`students`.first_name,
`students`.last_name,
`students_have_courses`.courses_course_id,
`students_have_courses`.s_date,
`students_have_courses`.e_date,
`students_have_courses`.int_date
FROM
`students`
LEFT OUTER JOIN `students_have_courses`
ON (
`students_have_courses`.`students_student_id` = `students`.`student_id` AND ((
`students_have_courses`.`s_date` >= `students`.`status_change_date` AND
`students`.current_status = 'Retread' ) OR
`students`.current_status = 'Active')
)
WHERE
`students`.current_status = 'Active' OR
`students`.current_status = 'Retread'
) `c_s_a_s`
ORDER BY
`c_s_a_s`.`courses_course_id` DESC
) `students_and_courses`
LEFT OUTER JOIN `students_have_optional_courses`
ON (
`students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND
`students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND
`students_have_optional_courses`.e_date IS NULL
)
GROUP BY
`students_and_courses`.student_id;
我想要返回的是所有活跃或重读学生的学生 ID、名字和姓氏,然后 LEFT JOIN 那些学生的最高 course_id、s_date、e_date 和 int_date,其中 s_date 自 status_change_date 如果状态是“翻新”。然后从 Students_have_Optional_courses 表中 LEFT JOIN 最高的Optional_courses_opcourse_id、s_date 和 e_date,其中 Students_have_Optional_courses.s_date 大于或等于 Students_have_courses.s_date 并且 Students_have_Optional_courses.e_date 为 NULL
这是返回的内容:
student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1
------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ----------
1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL
2 Jane Doe NULL NULL NULL NULL NULL NULL NULL
这是我想要返回的内容:
student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1
------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ----------
1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL
2 Jane Doe NULL NULL NULL NULL NULL NULL NULL
除了一件事之外,一切正常,无论我如何形成查询,我似乎都无法获得最高的 Students_have_Optional_courses.Optional_courses_opcourse_id
抱歉,我在写完这些内容后自己解决了这个问题,我认为这帮助我想到了解决方案。
这是解决方案查询:
SELECT
`students_and_courses`.student_id,
`students_and_courses`.first_name,
`students_and_courses`.last_name,
`students_and_courses`.courses_course_id,
`students_and_courses`.s_date,
`students_and_courses`.e_date,
`students_and_courses`.int_date,
`students_optional_courses`.optional_courses_opcourse_id,
`students_optional_courses`.s_date,
`students_optional_courses`.e_date
FROM (
SELECT
`c_s_a_s`.student_id,
`c_s_a_s`.first_name,
`c_s_a_s`.last_name,
`c_s_a_s`.courses_course_id,
`c_s_a_s`.s_date,
`c_s_a_s`.e_date,
`c_s_a_s`.int_date
FROM (
SELECT
`students`.student_id,
`students`.first_name,
`students`.last_name,
`students_have_courses`.courses_course_id,
`students_have_courses`.s_date,
`students_have_courses`.e_date,
`students_have_courses`.int_date
FROM
`students`
LEFT OUTER JOIN `students_have_courses`
ON (
`students_have_courses`.`students_student_id` = `students`.`student_id` AND ((
`students_have_courses`.`s_date` >= `students`.`status_change_date` AND
`students`.current_status = 'Retread' ) OR
`students`.current_status = 'Active')
)
WHERE
`students`.current_status = 'Active' OR
`students`.current_status = 'Retread'
) `c_s_a_s`
ORDER BY
`c_s_a_s`.`courses_course_id` DESC
) `students_and_courses`
LEFT OUTER JOIN (
SELECT
*
FROM
`students_have_optional_courses`
ORDER BY
`students_have_optional_courses`.optional_courses_opcourse_id DESC
) `students_optional_courses`
ON (
`students_optional_courses`.students_student_id = `students_and_courses`.student_id AND
`students_optional_courses`.s_date >= `students_and_courses`.s_date AND
`students_optional_courses`.e_date IS NULL
)
GROUP BY
`students_and_courses`.student_id;
最佳答案
这是我自己调试时发现的答案:
SELECT
`students_and_courses`.student_id,
`students_and_courses`.first_name,
`students_and_courses`.last_name,
`students_and_courses`.courses_course_id,
`students_and_courses`.s_date,
`students_and_courses`.e_date,
`students_and_courses`.int_date,
`students_optional_courses`.optional_courses_opcourse_id,
`students_optional_courses`.s_date,
`students_optional_courses`.e_date
FROM (
SELECT
`c_s_a_s`.student_id,
`c_s_a_s`.first_name,
`c_s_a_s`.last_name,
`c_s_a_s`.courses_course_id,
`c_s_a_s`.s_date,
`c_s_a_s`.e_date,
`c_s_a_s`.int_date
FROM (
SELECT
`students`.student_id,
`students`.first_name,
`students`.last_name,
`students_have_courses`.courses_course_id,
`students_have_courses`.s_date,
`students_have_courses`.e_date,
`students_have_courses`.int_date
FROM
`students`
LEFT OUTER JOIN `students_have_courses`
ON (
`students_have_courses`.`students_student_id` = `students`.`student_id` AND ((
`students_have_courses`.`s_date` >= `students`.`status_change_date` AND
`students`.current_status = 'Retread' ) OR
`students`.current_status = 'Active')
)
WHERE
`students`.current_status = 'Active' OR
`students`.current_status = 'Retread'
) `c_s_a_s`
ORDER BY
`c_s_a_s`.`courses_course_id` DESC
) `students_and_courses`
LEFT OUTER JOIN (
SELECT
*
FROM
`students_have_optional_courses`
ORDER BY
`students_have_optional_courses`.optional_courses_opcourse_id DESC
) `students_optional_courses`
ON (
`students_optional_courses`.students_student_id = `students_and_courses`.student_id AND
`students_optional_courses`.s_date >= `students_and_courses`.s_date AND
`students_optional_courses`.e_date IS NULL
)
GROUP BY
`students_and_courses`.student_id;
我需要在 LEFT JOINING 之前选择并订购 Students_have_Optional_courses 表。我希望这可以帮助任何其他人寻找这样的答案。
关于MySQL LEFT OUTER JOIN 虚拟表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13364913/