mysql - SQL 产生所需的输出

Question

来自如下所示的数据(在 MySQL 数据库中):

mysql> select * from test;
+------------+--------+
| start      | name   |
+------------+--------+
| 2013-04-01 | Donald |
| 2013-04-02 | Daisy  |
| 2013-04-03 | Mickey |
| 2013-04-03 | Minnie |
| 2013-04-01 | Pluto  |
| 2013-04-02 | Goofy  |
+------------+--------+
6 rows in set (0.00 sec)

我想编写一个查询来生成如下所示的输出:

2013-04-01  2013-04-02  2013-04003
----------  ----------  ----------
Donald      Daisy       Mickey
Pluto       Goofy       Minnie

有人可以建议 SQL 查询来生成此输出吗？

如果有帮助，这是我用来创建示例数据的代码。

create table test (
    start date,
    name varchar (20));

insert into test values ('2013-04-01','Donald');
insert into test values ('2013-04-02','Daisy');
insert into test values ('2013-04-03','Mickey');
insert into test values ('2013-04-03','Minnie');
insert into test values ('2013-04-01','Pluto');
insert into test values ('2013-04-02','Goofy');`

Answer 1

必须有一个数据透视表或一系列 case 语句。

Select 
      Case When Start = '2013-04-01' Then name End As '2013-04-01',
      Case When Start = '2013-04-02' Then name End As '2013-04-02',
      Case When Start = '2013-04-03' Then name End As '2013-04-03'
From Test;

如果表更复杂，动态生成此值会更困难。通过简单地导出到 Excel 并使用数据透视表功能，可以更轻松地处理较大的数据。