不是最有经验的 PHP 风格的人,但是由于需要和要求,我已经慢慢开始为内部/外部项目构建一个“登录”系统。
用户登录后,就可以根据三个数据字段搜索扫描的 TIF 图像;由于表中有多个客户,我想将查询限制为登录用户“客户代码”
$sql = "SELECT * FROM $tbl_name WHERE username = '$username' and password = '$md5'";
$result = mysql_query($sql);
$count = mysql_num_rows($result);
if($count == 1) {
$_SESSION['username'] = strtoupper($username);
$_SESSION['loggedin'] = TRUE;
$_SESSION['customercode'] = $result['customercode'];
header('location:home.php');
} else {
echo '<h1>Wrong Username or Password</h1>';
}
简单的登录机制按预期工作并应用适当的 $_SESSION['username'] = strtoupper($username);
但似乎无法从中获取行 customercode
$result
能够正确显示吗?
来自 mysql 数据库的 SELECT 查询是否可以用作 session 变量?
谢谢-
最佳答案
您需要使用mysql_fetch_*来获取customeCode:
$result = mysql_query($sql);
$count = mysql_num_rows($result);
if($count == 1) {
$data = mysql_fetch_array($result); //add this line
$_SESSION['username'] = strtoupper($username);
$_SESSION['loggedin'] = TRUE;
$_SESSION['customercode'] = $data['customercode'];
}
Note: As on most of the question all are recommend, I also recommend to you to use the mysqli_* or PDO instead of mysql_*
关于php - 从选择查询设置变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18058953/