我有一个查询,要查找 Sugarcrm 中铅的所有注释。根据屏幕截图,线索有 3 或 4 个注释。
我想根据潜在客户的 ID 将所有注释连接到一行(名称列)中。
我的查询是,
SELECT l.first_name, l.last_name, l.id, n.name, n.description
FROM
leads AS l inner join notes as n on l.id = n.parent_id
where l.deleted = 0
and n.deleted = 0
and l.id='104c4b25-adab-32f3-16ee-50d098a5dd5d'
最佳答案
您可以使用group_concat()功能
SELECT l.first_name, l.last_name, l.id, group_concat(n.name), n.description
FROM
leads AS l inner join notes as n on l.id = n.parent_id
where l.deleted = 0
and n.deleted = 0
and l.id='104c4b25-adab-32f3-16ee-50d098a5dd5d'
group by l.id
关于mysql - 根据潜在客户的 ID 将所有注释连接到一行中?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22398974/