php - 合并两个 MySQL 查询并将结果相减

Question

我的第一个查询返回一周的平均值:

SELECT POSITION, PLAYER, SUM( POINTS ) / COUNT( DISTINCT YEAR, WEEK ) AS  'avg' 
FROM SCHEDULE WHERE WEEK = 1 GROUP BY PLAYER HAVING COUNT( DISTINCT YEAR, WEEK ) >2 
ORDER BY avg DESC

我的第二个查询返回总体平均值:

SELECT POSITION, PLAYER, SUM( POINTS ) / COUNT( DISTINCT YEAR, WEEK ) AS  'avg' 
FROM SCHEDULE GROUP BY PLAYER HAVING COUNT( DISTINCT YEAR, WEEK ) >2 
ORDER BY avg DESC

我希望从查询 2 中减去查询 1 并按降序显示结果。

Answer 1

SELECT 
    WA.POSITION, 
    WA.PLAYER, 
    WA.avg as 'wk_avg',
    OA.avg as 'overall_avg',
    WA.avg - OA.avg as 'diff'
FROM 
    (SELECT POSITION, PLAYER, SUM( POINTS ) / COUNT( DISTINCT YEAR, WEEK ) AS  'avg' 
    FROM SCHEDULE WHERE WEEK = 1 GROUP BY PLAYER HAVING COUNT( DISTINCT YEAR, WEEK ) >2 
    ) WA
INNER JOIN
    (SELECT POSITION, PLAYER,SUM( POINTS ) / COUNT( DISTINCT YEAR, WEEK ) AS  'avg' 
    FROM SCHEDULE GROUP BY PLAYER HAVING COUNT( DISTINCT YEAR, WEEK ) >2 
    ) OA
ON WA.POSITION = OA.POSITION and WA.PLAYER = OA.PLAYER
ORDER BY WA.avg - OA.avg DESC