我有两个表:
每副牌组(卡牌)始终属于某个玩家(一名玩家可以拥有 1..* 副牌)。此外,每个玩家总是有一套(而且只有一套)活跃套牌。
我想添加一个新玩家,但如果我只执行 INSERT INTO Players(...) VALUES (...)
,我将没有 active_deck_id
code> 应插入此查询中。同样,如果我从 decks
开始,我就不会有 player_id
。
这就是我决定使用事务(在过程中)的原因:
CREATE PROCEDURE `add_player` (IN login VARCHAR(255), IN password VARCHAR(255),
OUT player_id INT(11))
BEGIN
START TRANSACTION;
INSERT INTO `players` (id, `login`, `password`, registered, last_logged, active_deck_id)
VALUES ('', login, pass, now(), now(), 0);
SET player_id = LAST_INSERT_ID();
INSERT INTO `decks` (id, name, player_id) VALUES ('', `sample deck`, player_id);
COMMIT;
END
END
然后我刚刚调用它:
set @login = 'mylogin';
set @pass = 'pass';
call add_player(@login, @pass, @id);
...但我收到错误:
#1452 - Cannot add or update a child row: a foreign key constraint fails (`game`.`players`, CONSTRAINT `active_deck` FOREIGN KEY (`active_deck_id`) REFERENCES `decks` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION)
那么,如何进行所有插入,然后检查外键约束?因为在第一次插入之后,约束应该被打破,但在整个事务之后,它们应该没问题。 p>
我的表的 SQL:
CREATE TABLE IF NOT EXISTS `game`.`decks` (
`id` INT UNSIGNED NOT NULL AUTO_INCREMENT,
`name` VARCHAR(255) NOT NULL,
`player_id` INT UNSIGNED NOT NULL,
PRIMARY KEY (`id`, `player_id`),
INDEX `player` (`player_id` ASC),
CONSTRAINT `player`
FOREIGN KEY (`player_id`)
REFERENCES `game`.`players` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS `game`.`players` (
`id` INT UNSIGNED NOT NULL AUTO_INCREMENT,
`login` VARCHAR(255) NOT NULL,
`password` VARCHAR(255) NOT NULL,
`registered` DATETIME NOT NULL,
`last_logged` DATETIME NOT NULL,
`active_deck_id` INT UNSIGNED NOT NULL,
PRIMARY KEY (`id`),
INDEX `active_deck` (`active_deck_id` ASC),
CONSTRAINT `active_deck`
FOREIGN KEY (`active_deck_id`)
REFERENCES `game`.`decks` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
最佳答案
尝试这个命令
设置 FOREIGN_KEY_CHECKS = 0;
在进行插入之前,请将值设置为 1 将其打开。
关于mysql - 如何进行所有插入然后检查外键约束? (SQL 事务因外键约束而失败),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28310178/