php - Zend Framework 1. 获取评论

Question

我无法创建一个适当的查询来选择与一张特定图像相关的所有评论并获取这些评论的作者。 我想创建一个类似的查询:

select a comment where comment_id == image_id && user_id(table comments) == user_id(table users)

这是 MySQL 部分:

Table 'comments'
id | comment | user_id | image_id |
1  | test 1  |    1    |     1    |
2  | test 2  |    1    |     2    |
3  | test 3  |    2    |     1    |


Table 'users'
id |  name  |
1  |  test1 |
2  |  test2 |


Table 'images'
id |    img     |
1  |  test.jpg  |
2  |  test.jpg  |
3  |  test.jpg  |
4  |  test.jpg  |

Controller 部分:

$imageId = $filter->filter ($request->getParam('id'));
$this->view->imageId = $filter->filter ($request->getParam('id'));
$this->view->imageChosen = $images->fetchRow($images->select()->where('id = ?', $imageId));

$users = new Users();
$userChosen = new Users();
$comments = new Comments();
$this->view->comments = $comments->fetchAll();

$this->view->userChosen = $users->fetchRow($users->select()->where('id = ?', $this->view->imageChosen->author_id));
$this->view->commentsChosen = $comments->fetchAll($comments->select()->where('id = ?', $imageId));

查看部分:

for ($i=0; $i < count($this->commentsChosen); $i++) {
    echo $this->commentChosen[$i]->comment;
}

现在我只收到第一条评论。 我的意思是我需要属于每张图片的所有评论以及作者信息。 感谢您的帮助!

Answer 1

正如您所说，您可以通过查询获取图像信息，我将扩展它以便也获取用户信息:

$select = $comments->select()->setIntegrityCheck(false)
                   ->from('comments')
                   ->joinInner('users', 'users.id = comments.user_id')
                   ->where('comments.image_id = ?', $this->view->imageChosen->id);

$this->view->commentsChosen = $comments->fetchAll($select);

生成的查询将是:

SELECT comments.* users.* FROM comments
INNER JOIN users ON users.id = comments.user_id
WHERE comments.image_id = [Your_id_here]

希望这会有所帮助!