php - mysql - 返回分组在列中的结果

标签 php mysql search search-engine

我正在开发搜索/标签系统。我最初编写的查询是在我的文章/视频表中存储“标题”、“描述”和逗号分隔的“标签”列时执行的。从那以后,我意识到标准化标签的好处。我现在有三个表要处理...

tbl_Articles

  • article_id
  • 标题
  • 描述
  • 内容

tbl_tag_index

  • tag_id(代理主 ID)
  • tag_type(tbl_Articles 等于 1, 2 个用于 tbl_videos)
  • tag_word_id(见下表)
  • tag_target_id (article_id/video_id - 取决于 tag_type)

tbl_tag_word

  • tag_word_id
  • tag_word(最后是实际标签)

此查询返回标签...唯一的问题是它将它们作为不同的行返回。我想我需要将结果分组到同一行,以便我的搜索查询可以工作

SELECT * 
  FROM `tbl_articles` A 
  JOIN `tag_index` I ON A.article_id = I.tag_target_id 
  JOIN tag_word W ON I.tag_word_id = W.tag_word_id 
 WHERE I.tag_type_id = 1

这是我的旧搜索查询

SELECT *, 
(
(CASE WHEN `description` LIKE '%hotel%' THEN 1 ELSE 0 END) + 
(CASE WHEN `description` LIKE '%london%' THEN 1 ELSE 0 END) + 
(CASE WHEN `description` LIKE '%lazy%' THEN 1 ELSE 0 END) + 
(CASE WHEN `description` LIKE '%dog%' THEN 1 ELSE 0 END) +

(CASE WHEN `title` LIKE '%hotel%' THEN 1 ELSE 0 END) + 
(CASE WHEN `title` LIKE '%london%' THEN 1 ELSE 0 END) + 
(CASE WHEN `title` LIKE '%lazy%' THEN 1 ELSE 0 END) + 
(CASE WHEN `title` LIKE '%dog%' THEN 1 ELSE 0 END) +

(CASE WHEN `tags` LIKE '%hotel%' THEN 1 ELSE 0 END) + 
(CASE WHEN `tags` LIKE '%london%' THEN 1 ELSE 0 END) + 
(CASE WHEN `tags` LIKE '%lazy%' THEN 1 ELSE 0 END) + 
(CASE WHEN `tags` LIKE '%dog%' THEN 1 ELSE 0 END)

) AS relevance
FROM `tbl_Articles`
WHERE `description` LIKE '%hotel%'
  OR `description` LIKE '%london%'
  OR `description` LIKE '%lazy%'
  OR `description` LIKE '%dog%' 
  OR `title` LIKE '%hotel%'
  OR `title` LIKE '%london%'
  OR `title` LIKE '%lazy%'
  OR `title` LIKE '%dog%'
  OR `tags` LIKE '%hotel%'
  OR `tags` LIKE '%london%'
  OR `tags` LIKE '%lazy%'
  OR `tags` LIKE '%dog%'
ORDER BY relevance DESC
LIMIT 0 , 10;

最佳答案

用途:

SELECT A.*, 
       GROUP_CONCAT(DISTINCT w.tag_word ORDER BY w.tag_word ASC SEPARATOR ',') AS tags,
       COUNT(DISTINCT w.tag_word) +
       (CASE WHEN `description` LIKE '%hotel%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `description` LIKE '%london%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `description` LIKE '%lazy%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `description` LIKE '%dog%' THEN 1 ELSE 0 END) +

       (CASE WHEN `title` LIKE '%hotel%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `title` LIKE '%london%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `title` LIKE '%lazy%' THEN 1 ELSE 0 END) + 
       (CASE WHEN `title` LIKE '%dog%' THEN 1 ELSE 0 END) AS relevance
  FROM tbl_articles A 
  JOIN tag_index I ON A.article_id = I.tag_target_id 
  JOIN tag_word W ON I.tag_word_id = W.tag_word_id 
 WHERE I.tag_type_id = 1
   AND w.tag_word IN ('hotel', 'london', 'lazy', 'dog')
GROUP BY a.article_id, a.title, a.description, a.content
ORDER BY relevance DESC

关于php - mysql - 返回分组在列中的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2066789/

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