php - 从三表SQL中获取数据

Question

我的MySQL表结构(3个表)

用户

id
username

图像

id
user_id
image

用户关注

id
user_id
follow_id

我尝试进行查询，该查询为我提供“images”表中我(user_id = 3)和我关注“user_follow”表的 friend 的所有图像

现在查询，它给了我我关注的用户的所有图片，我不知道要添加哪些更改才能返回我的图像(我的 user_id = 3)。所有用户名必须在用户名(不是id)中，用户名在“users”表中

 $sql = "SELECT u.username, p.image, p.date
    FROM users u, user_follow f, images p
    WHERE f.user_id = 3 AND f.follow_id = u.id AND f.follow_id = p.user_id
    ORDER BY p.date DESC";

返回:

[0] => Array
    (
        [id] => 8
        [image] => fsfsf
        [date] => 2012-01-24 14:58:14
    )

[1] => Array
    (
        [id] => 7
        [image] => first.jpg
        [date] => 2012-01-24 14:42:27
    )

[2] => Array
    (
        [id] => 7
        [image] => second.jpg
        [date] => 2012-01-24 14:42:27
    )

[3] => Array
    (
        [id] => 6
        [image] => the_last.jpg
        [date] => 2012-01-24 01:49:45
    )

我关注的用户及其图像，但没有来 self 的 user_id 的图像

Answer 1

SELECT
   images.*,
   users.username
FROM images
LEFT JOIN users ON images.user_id = users.id
LEFT JOIN user_follow ON images.user_id = user_follow.follow_id
WHERE images.user_id = 3 OR user_follow.user_id = 3
ORDER BY images.date DESC