mysql - 是否有一种性能友好的方法来列出数据库中每个字母的结果？

Question

我想创建一个索引页，其中包含字母表中每个字母的几个结果。

目前我有这个:

SELECT url_slug, name FROM artists WHERE name LIKE "A%" ORDER BY rand() LIMIT 10 
SELECT url_slug, name FROM artists WHERE name LIKE "B%" ORDER BY rand() LIMIT 10 
SELECT url_slug, name FROM artists WHERE name LIKE "C%" ORDER BY rand() LIMIT 10 
SELECT url_slug, name FROM artists WHERE name LIKE "D%" ORDER BY rand() LIMIT 10 
SELECT url_slug, name FROM artists WHERE name LIKE "E%" ORDER BY rand() LIMIT 10 
SELECT url_slug, name FROM artists WHERE name LIKE "F%" ORDER BY rand() LIMIT 10 

是否有另一种性能更友好的方法来实现这一目标？

P.s.我知道“order by rand()”不太好。但这还只是在开发中。

Answer 1

对于您想要达到的目的，查询并没有比 IMO 更好。然而，如果表很大，可能需要临时创建一个缓存表来单独保存固定字母的值。

建立索引，根据字段为您的记录建立索引。