mysql - 从 2 个具有不同条件的表中选择

Question

我尝试了大约 2 个小时，但没有成功。这是我需要做的示例:

表格

人员:

nameA           score
---------------------
someone1        24
someone2        24
someone3        24
someone4        23
someone5        21
someone6        24
someone7        19
someone8        20
someone9        24
someone10       24

运行:

nameB           add
---------------------
someone1        s
someone2
someone2
someone4        s
someone5
someone4
someone7        s
someone8        s
someone7
someone7        s

请注意，这只是一个直观地展示我的问题的示例。无需谈论我的 table 设置。

我想知道:
首先，我需要表 people 中分数小于 24 的所有条目(到这里为止很简单)。

下一步是仅显示 people.name 在表 runs 中没有 s 的结果(我的实际问题)。

输出应该是:

name            score
---------------------
someone2        22      /*  no "s"-entry in runs        */
someone5        21      /*  also no entries             */

不幸的是我对连接不太熟悉。 这是我最后一次尝试:

SELECT nameA,score FROM runs,people WHERE people.nameA = runs.nameB
AND people.score < 24
AND runs.add != "s"
GROUP BY people.nameA

伪代码:

foreach Person in (SELECT nameA as Person,score FROM people WHERE score < 24)
SHOW name.B = Person WHERE add != "s"

我知道这很糟糕:)。但它用两行描述了我需要的内容。

如果有任何帮助，我将不胜感激。
谢谢!

Answer 1

select * from people where score<24 and 
name in (select name from runs where add!=s) and
name not in (select name from runs where add=s)