php - DELETE FROM table WHERE IN() 准备语句仅删除数组的第一个值

Question

通过ajax你可以得到$_POST的数组。

这是我的代码。

<?php
include 'connect.php';
$deletethesestring = '';
foreach ($_POST as $v)
{

    $deletethesestring .= $v.',';

}

$deletethesestring  = rtrim($deletethesestring ,',');

echo $deletethesestring;



$deleteprizesqry = $pdo->prepare('DELETE FROM tbname where tbname_id IN(:deletethesestring);');
$deleteprizesqry  -> bindParam(':deletethesestring', $deletethesestring);

$deleteprizesqry->execute();
?>

如果我的数组例如是 [9,7,3,4,8,5] 我的代码只删除了 9. 其余的仍然保留。我希望它删除 id 属于数组的每一行。我该怎么做？

Answer 1

请尝试以下代码:

<?php
include 'connect.php';
$deletethesestring = '';
foreach ($_POST as $v)
{

    $deletethesestring .= $v.',';

}

$deleteIds  = rtrim($deletethesestring ,',');

$deletethesestring = join(',', array_fill(0, count($_POST), '?'));

$delQry = "DELETE FROM tbname where tbname_id IN($deletethesestring)";
$deleteprizesqry = $pdo->prepare($delQry);
$deleteprizesqry->execute($_POST);

希望这对您有帮助!