mysql - 联合选择列不匹配

Question

这是我的查询:

SELECT
    FROM_UNIXTIME( date_added,  '%m-%d-%Y' ) AS formatted_date,
    SUM( tb =1 ) AS sum_users,
    SUM( tb =2 ) AS sum_links,
    SUM( tb =3 ) AS sum_ads,
    SUM( tb =4 ) AS sum_actions
FROM (
    SELECT date_added, 1 AS tb
        FROM users_list WHERE 1=1
    UNION ALL 
    SELECT date_added, 2
        FROM users_links WHERE 1=1
    UNION ALL 
    SELECT date_served, 3
        FROM ads_served WHERE 1=1
    UNION ALL 
    SELECT date_served, 4
        FROM actions WHERE 1=1
) AS t
GROUP BY formatted_date
ORDER BY formatted_date DESC

这是我的表格数据:

用户列表

id    date_added
1     1234567890
2     1334567890
3     1434567890

用户链接

id    date_added
1     1244567890
2     1354567890
3     1464567890

广告转换

id    date_served    revenue
1     1234567891     0.01
2     1334567892     0.02
3     1434567893     0.02

行动

id    date_served
1     1234561890
2     1334562890
3     1434563890

我尝试将 ads_served 表中 formatted_date 的收入求和，作为输出查询的第六列。我不知道从哪里开始。如果我将总和(收入)添加到联合选择中，我会收到“列不匹配”错误。

Answer 1

revenue 列属于 ads_served，但您从不存在 revenue 的子查询中进行选择。将其添加到子查询中:

SELECT
    FROM_UNIXTIME( date_added,  '%m-%d-%Y' ) AS formatted_date,
    SUM( tb =1 ) AS sum_users,
    SUM( tb =2 ) AS sum_links,
    SUM( tb =3 ) AS sum_ads,
    SUM( tb =4 ) AS sum_actions,
    SUM( revenue ) As sum_revenue
FROM (
    SELECT date_added, 1 AS tb, 0 As revenue
        FROM users_list WHERE 1=1
    UNION ALL 
    SELECT date_added, 2, 0
        FROM users_links WHERE 1=1
    UNION ALL 
    SELECT date_served, 3, revenue
        FROM ads_served WHERE 1=1
    UNION ALL 
    SELECT date_served, 4, 0
        FROM actions WHERE 1=1
) AS t
GROUP BY formatted_date
ORDER BY formatted_date DESC