php - MySQL (PDO) exec 不返回任何内容，没有错误，没有添加行

Question

嗯，我在 SO 上发现了类似的问题，但它仍然不起作用。

我运行以下代码，然后...什么也没有!没有错误，没有插入任何内容。

这是 PHP 代码:

    try
    {
        $obj_sqlsvr = new PDO('mysql:host=localhost;dbname=svmsys', 'root', '');
    }
    catch(Exception $e)
    {
        echo 'Erreur : '.$e->getMessage();
    }



    $servcatid = $_POST["servcatid"];
$sysname = $_POST["sysname"];
$sortorder = 1;
$friendlyname_fr = $_POST["friendlyname_fr"];
$friendlyname_en = $_POST["friendlyname_en"];


$fee_billtime = $_POST["fee_billtime"];
$fee_ot = isset($_POST["fee_ot"]) ? $_POST["fee_ot"] : 0;
$fee_1m = isset($_POST["fee_1m"]) ? $_POST["fee_1m"] : 0;
$fee_3m = isset($_POST["fee_3m"]) ? $_POST["fee_3m"] : 0;
$fee_6m = isset($_POST["fee_6m"]) ? $_POST["fee_6m"] : 0;
$fee_12m = isset($_POST["fee_12m"]) ? $_POST["fee_12m"] : 0;
$fee_24m = isset($_POST["fee_24m"]) ? $_POST["fee_24m"] : 0;
$fee_36m = isset($_POST["fee_36m"]) ? $_POST["fee_36m"] : 0;
$fee_other = isset($_POST["fee_other"]) ? $_POST["fee_other"] : 0;

$adm_timeadded = time();
$adm_addedby = 1;
$adm_active = $_POST["adm_active"];
$adm_start = $_POST["adm_start"];
$adm_expires = $_POST["adm_expires"];
$adm_soldlmt = $_POST["adm_soldlmt"];



    try
    {
        $req = $obj_sqlsvr->prepare("INSERT INTO pricelist(id, servcatid, sortorder, sysname, friendlyname_fr, friendlyname_en, fee_ot, fee_1m, fee_3m, fee_6m, fee_12m, fee_24m, fee_36m, fee_other, fee_billtime, adm_timeadded, adm_addedby, adm_active, adm_start, adm_expires, adm_soldlmt)
                VALUES(NULL, :servcatid,:sortorder,:sysname,:friendlyname_fr,:friendlyname_en,:fee_ot,:fee_1m,:fee_3m,:fee_6m,:fee_12m,
:fee_24m,:fee_36m,:fee_other,:fee_billtime,:adm_timeadded,:adm_addedby,:adm_active,:adm_start,:adm_expires,:adm_soldlmt)");
        $req->bindParam(':servcatid', $servcatid);
        $req->bindParam(':sortorder', $sortorder);
        $req->bindParam(':sysname', $sysname);
        $req->bindParam(':friendlyname_fr', $friendlyname_fr);
        $req->bindParam(':friendlyname_en', $friendlyname_en);
        $req->bindParam(':fee_ot', $fee_ot);
        $req->bindParam(':fee_1m', $fee_1m);
        $req->bindParam(':fee_3m', $fee_3m);
        $req->bindParam(':fee_6m', $fee_6m);
        $req->bindParam(':fee_12m', $fee_12m);
        $req->bindParam(':fee_24m', $fee_24m);
        $req->bindParam(':fee_36m', $fee_36m);
        $req->bindParam(':fee_other', $fee_other);
        $req->bindParam(':fee_billtime', $fee_billtime);
        $req->bindParam(':adm_timeadded', $adm_timeadded);
        $req->bindParam(':adm_addedby', $adm_addedby);
        $req->bindParam(':adm_active', $adm_active);
        $req->bindParam(':adm_start', $adm_start);
        $req->bindParam(':adm_expires', $adm_expires);
        $req->bindParam(':adm_soldlmt', $adm_soldlmt);
        $res = $req->execute();
    }
    catch(Exception $e)
    {
        echo 'Erreur : '.$e->getMessage();
    }

表结构:

表结构(再次)采用 SQL 格式:

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";
CREATE TABLE IF NOT EXISTS `pricelist` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `servcatid` int(11) NOT NULL,
  `order` int(11) DEFAULT NULL,
  `sysname` varchar(100) NOT NULL,
  `friendlyname_fr` varchar(100) NOT NULL,
  `friendlyname_en` varchar(100) NOT NULL,
  `fee_ot` decimal(10,2) DEFAULT NULL,
  `fee_1m` decimal(10,2) DEFAULT NULL,
  `fee_3m` decimal(10,2) DEFAULT NULL,
  `fee_6m` decimal(10,2) DEFAULT NULL,
  `fee_12m` decimal(10,2) DEFAULT NULL,
  `fee_24m` decimal(10,2) DEFAULT NULL,
  `fee_36m` decimal(10,2) DEFAULT NULL,
  `fee_other` decimal(10,4) DEFAULT NULL,
  `fee_billtime` int(2) NOT NULL DEFAULT '0',
  `adm_timeadded` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `adm_addedby` int(11) NOT NULL,
  `adm_active` tinyint(1) NOT NULL DEFAULT '1',
  `adm_start` datetime DEFAULT NULL,
  `adm_expires` datetime DEFAULT NULL,
  `adm_soldlmt` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ;

你看到任何错误了吗？如果是的话，你能告诉我它在哪里吗？

非常感谢， 杰里米

编辑 我已在代码和表结构中将字段“order”重命名为“sortorder”(感谢 Pekka)，因为它是保留字。仍然无法工作。

编辑 在准备和执行命令周围添加 Try/Catch。/使用 echo 命令代替 die 命令来显示错误。 (感谢大卫·斯特拉坎)

编辑 查询中缺少 '(感谢 Drew Pierce)

编辑 PDO 查询现已参数化(感谢 Andy Lester)，仍然没有错误消息，表中也没有行。

示例查询(使用 phpMyAdmin)

INSERT INTO pricelist(id, servcatid, sysname, sortorder, friendlyname_fr, friendlyname_en, fee_ot, fee_1m, fee_3m, fee_6m, fee_12m, fee_24m, fee_36m, fee_other, fee_billtime, adm_timeadded, adm_addedby, adm_active, adm_start, adm_expires, adm_soldlmt)
VALUES(NULL, '2','demo',NULL,'DEMO','DEMO', '12','','','','','','','','1', '1353533266','1','1','','','1')

Answer 1

参见this post关于如何使PDO输出错误消息。

您的具体错误是 order 是 mySQL 中的保留字。