我有一个页面,我正在尝试从数据库中提取与该页面相关的文章。我有一个 SQL 查询来提取我需要的内容,但我不断收到错误“‘where 子句’中的未知列‘时尚’”。我相信我需要将其转换为,
$FilteredStories = DB::query(' SELECT C.ID, C.URLSegment, C.Title, B.Title AS "Category"
FROM `articlepage_categories` AS A
JOIN articlecategory AS B ON A.ArticleCategoryID = B.ID
JOIN sitetree AS C ON A.ArticlePageID = C.ID
WHERE B.Title = "Fashion" LIMIT 5')
->value();
进入 SQLQuery 抽象层,但我不知道如何。有人可以告诉我如何创建具有多个连接的 SQLQuery 抽象层吗?
注释
- 我使用的是 Silverstripe 版本 3.6.1
- “时尚”目前是硬编码的,但将被替换为 我将传入的变量。
最佳答案
SilverStripe的数据库默认使用ANSI
sql_mode
,其中字符串文字需要用单引号括起来。您需要将 "Fashion"
周围的双引号替换为单引号,如下所示:
$FilteredStories = DB::query('SELECT C.ID, C.URLSegment, C.Title, B.Title AS "Category"
FROM `articlepage_categories` AS A
JOIN articlecategory AS B ON A.ArticleCategoryID = B.ID
JOIN sitetree AS C ON A.ArticlePageID = C.ID
WHERE B.Title = \'Fashion\' LIMIT 5')
此处转义,因为外引号是单引号。
您的查询将用 SQLSelect
表示,如下所示:
$filteredStories = SQLSelect::create();
$filteredStories->selectField('"sitetree"."ID", "sitetree"."URLSegment", "sitetree"."Title", "articlecategory"."Title" AS "Category"');
$filteredStories->setFrom('articlepage_categories');
$filteredStories->addLeftJoin('articlecategory', '"articlecategory"."ID" = "articlepage_categories"."ArticleCategoryID"');
$filteredStories->addLeftJoin('sitetree','"sitetree"."ID" = "articlepage_categories"."ArticlePageID"');
$filteredStories->addWhere('"articlecategory"."Title" = \'Fashion\'');
$filteredStories->setLimit(5);
关于php - 如何将原始 SQL 查询转换为 Silverstripe SQLQuery 抽象层,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50238317/