sql - 联合不同的行，但按 mysql 中出现的次数对它们进行排序

Question

我有以下查询:

SELECT o.id,o.name FROM object o 
WHERE 
    (
        o.description LIKE '%Black%' OR
        o.name LIKE '%Black%'
    ) 
UNION ALL
SELECT o2.id,o2.name FROM object o2
WHERE 
    (
        o2.description LIKE '%iPhone%' OR
        o2.name LIKE '%iPhone%'
    ) 

这会产生以下结果:

id  name
2   New Black iPhone
1   New White iPhone
2   New Black iPhone

我想要 UNION DISTINCT，但我也想要按每个相同行的出现次数(主:id)排序的结果。

Answer 1

您可以根据 id 和 name 列对结果进行分组，并查看每个不同值出现的次数。 然后您可以按照最先出现的次数对它们进行排序 order by count(*) desc

select id, name, count(*) as occurences
from (
    SELECT o.id,o.name FROM object o 
    WHERE 
        (
            o.description LIKE '%Black%' OR
            o.name LIKE '%Black%'
        ) 
    UNION ALL
    SELECT o2.id,o2.name FROM object o2
    WHERE 
        (
            o2.description LIKE '%iPhone%' OR
            o2.name LIKE '%iPhone%'
        ) 
)
group by id, name
order by count(*) desc

这将返回

id  name              occurences
2   New Black iPhone  2
1   New White iPhone  1