IF NOT EXISTS(SELECT * FROM `user` WHERE `name`='Rutvij' AND `lang`='python')
BEGIN
INSERT INTO `user` VALUES ('Rutvij', 'python', 25)
END
ELSE
BEGIN
UPDATE user SET `name`='Kanzaria' WHERE `name`='Rutvij'
END
我正在 phpmyadmin sql 区域尝试上述查询。我正在使用xampp。它抛出错误,指出
1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'IF EXISTS(SELECT * FROM user) SELECT name FROM use' at line 1
我也尝试过下面的代码
IF NOT EXISTS(SELECT * FROM user WHERE name='Rutvij' AND lang='python')
BEGIN
INSERT INTO user VALUES ('Rutvij', 'python', 25)
END
ELSE
BEGIN
INSERT INTO user VALUES ('Kanzaria', 'python', 25)
END
奋斗了这么久。请帮忙。谢谢!!
最佳答案
MySQL 不允许使用 if
逻辑,除非您处于编程 block (存储过程、触发器或函数)中。
幸运的是,您可以使用 WHERE
逻辑执行相同的操作:
INSERT INTO user
SELECT 'Rutvij', 'python', 25
FROM DUAL
WHERE NOT EXISTS (SELECT 1 FROM user WHERE name = 'Rutvij' AND lang = 'python')
UNION ALL
SELECT 'Kanzaria', 'python', 25
FROM DUAL
WHERE EXISTS (SELECT 1 FROM user WHERE name = 'Rutvij' AND lang = 'python');
MySQL 应在 INSERT
之前处理 SELECT
,因此只应插入一行。
或者,您可以将其作为两个 INSERT
执行,但顺序相反:
INSERT INTO user
SELECT 'Kanzaria', 'python', 25
FROM DUAL
WHERE EXISTS (SELECT 1 FROM user WHERE name = 'Rutvij' AND lang = 'python');
INSERT INTO user
SELECT 'Rutvij', 'python', 25
FROM DUAL
WHERE NOT EXISTS (SELECT 1 FROM user WHERE name = 'Rutvij' AND lang = 'python');
关于mysql - 如果不存在则不工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35819895/