我有以下查询结果:
+---------------+------+------+------+------+------+------+------+-------+
| order_main_id | S36 | S37 | S38 | S39 | S40 | S41 | S42 | total |
+---------------+------+------+------+------+------+------+------+-------+
| 26 | 127 | 247 | 335 | 333 | 223 | 111 | 18 | 1394 |
| 26 | 323 | 606 | 772 | 765 | 573 | 312 | 154 | 3505 |
| 38 | 25 | 35 | 35 | 35 | 20 | NULL | NULL | 150 |
| 38 | 25 | 35 | 35 | 35 | 20 | NULL | NULL | 150 |
| 39 | 65 | 86 | 86 | 42 | 21 | NULL | NULL | 300 |
| 39 | 42 | 58 | 58 | 28 | 14 | NULL | NULL | 200 |
| 35 | 11 | 20 | 21 | 18 | 9 | 2 | NULL | 81 |
| 35 | 10 | 25 | 30 | 23 | 12 | 1 | NULL | 101 |
+---------------+------+------+------+------+------+------+------+-------+
我想在输入不同的 order_main_id 之前插入一个 SUM，它会像这样的结果:
+---------------+------+------+------+------+------+------+------+-------+
| order_main_id | S36 | S37 | S38 | S39 | S40 | S41 | S42 | total |
+---------------+------+------+------+------+------+------+------+-------+
| 26 | 127 | 247 | 335 | 333 | 223 | 111 | 18 | 1394 |
| 26 | 323 | 606 | 772 | 765 | 573 | 312 | 154 | 3505 |
| | 450 | 853 | 1107 | 1098 | 796 | 423 | 172 | 4899 |
| 38 | 25 | 35 | 35 | 35 | 20 | NULL | NULL | 150 |
| 38 | 25 | 35 | 35 | 35 | 20 | NULL | NULL | 150 |
| | 50 | 70 | 70 | 70 | 40 | NULL | NULL | 300 |
| 39 | 65 | 86 | 86 | 42 | 21 | NULL | NULL | 300 |
| 39 | 42 | 58 | 58 | 28 | 14 | NULL | NULL | 200 |
| | 107 | 144 | 144 | 70 | 35 | NULL | NULL | 500 |
| 35 | 11 | 20 | 21 | 18 | 9 | 2 | NULL | 81 |
| 35 | 10 | 25 | 30 | 23 | 12 | 1 | NULL | 101 |
| | 21 | 45 | 51 | 41 | 21 | 3 | NULL | 182 |
+---------------+------+------+------+------+------+------+------+-------+
如何做到这一点？
最佳答案
您需要编写第二个使用 GROUP BY order_main_id 的查询。
类似于:
SELECT sum(S41+...) FROM yourTable GROUP BY orderMainId
K
关于sql - 如何从 MySQL 中为每 n 条记录求和，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1346117/