参见:Can I specify a meaningful name for an anonymous class in C#?
在 C# 中你可以这样写:
var e = new { ID = 5, Name= "Prashant" };
assertEquals( 5, e.ID )
但在 Scala 中我最终写成:
var e = (5, "Prashant")
assertEquals( 5, e._1 )
Scala 通过使用泛型来维护类型安全(C# 也是如此),但失去了每个字段名称的可读性,例如我使用“_1”而不是“ID”。
Scala 中有这样的东西吗?
最佳答案
object T {
def main(args: Array[String]) {
val e = new { var id = 5; var name = "Prashant" }
assert(e.id == 5)
}
}
好吧,让我们把事情说清楚。这确实在 Scala 2.7 和 Scala 2.8 上使用了反射,因为在这种情况下,e
的类型是 结构类型,Scala 通过反射处理它。这是清理时生成的代码 (scalac -Xprint:cleanup
):
package <empty> {
final class T extends java.lang.Object with ScalaObject {
private <synthetic> <static> var reflMethod$Cache1: java.lang.reflect.Method = null;
private <synthetic> <static> var reflClass$Cache1: java.lang.Class = null;
<synthetic> <static> def reflMethod$Method1(x$1: java.lang.Class): java.lang.reflect.Method = {
if (T.this.reflMethod$Cache1.eq(null).||(T.this.reflClass$Cache1.ne(x$1)))
{
T.this.reflMethod$Cache1 = x$1.getMethod("id", Array[java.lang.Class]{});
T.this.reflClass$Cache1 = x$1;
()
};
T.this.reflMethod$Cache1
};
@remote def $tag(): Int = scala.ScalaObject$class.$tag(T.this);
def main(args: Array[java.lang.String]): Unit = {
val e: java.lang.Object = {
new T$$anon$1()
};
scala.this.Predef.assert(scala.Int.unbox({
var exceptionResult1: java.lang.Object = _;
try {
exceptionResult1 = T.reflMethod$Method1(e.getClass()).invoke(e, Array[java.lang.Object]{})
} catch {
case ($1$ @ (_: java.lang.reflect.InvocationTargetException)) => {
exceptionResult1 = throw $1$.getCause()
}
};
exceptionResult1
}.$asInstanceOf[java.lang.Integer]()).==(5))
};
def this(): object T = {
T.super.this();
()
}
};
final class T$$anon$1 extends java.lang.Object {
private[this] var id: Int = _;
<accessor> def id(): Int = T$$anon$1.this.id;
<accessor> def id_=(x$1: Int): Unit = T$$anon$1.this.id = x$1;
private[this] var name: java.lang.String = _;
<accessor> def name(): java.lang.String = T$$anon$1.this.name;
<accessor> def name_=(x$1: java.lang.String): Unit = T$$anon$1.this.name = x$1;
def this(): T$$anon$1 = {
T$$anon$1.this.id = 5;
T$$anon$1.this.name = "Prashant";
T$$anon$1.super.this();
()
}
}
}
有一些缓存正在进行,但如果我在 id
和 name
之间交替,它已经使缓存无效。 Scala 2.8 也有反射和缓存,但它使用了更高效的缓存技术,应该能提供更好的整体性能。作为引用,这里是 Scala 2.8 的清理:
package <empty> {
final class T extends java.lang.Object with ScalaObject {
final private <synthetic> <static> var reflParams$Cache1: Array[java.lang.Class] = Array[java.lang.Class]{};
@volatile
private <synthetic> <static> var reflPoly$Cache1: scala.runtime.MethodCache = new scala.runtime.EmptyMethodCache();
<synthetic> <static> def reflMethod$Method1(x$1: java.lang.Class): java.lang.reflect.Method = {
var method1: java.lang.reflect.Method = T.reflPoly$Cache1.find(x$1);
if (method1.ne(null))
return method1
else
{
method1 = x$1.getMethod("id", T.reflParams$Cache1);
T.reflPoly$Cache1 = T.reflPoly$Cache1.add(x$1, method1);
return method1
}
};
def main(args: Array[java.lang.String]): Unit = {
val e: java.lang.Object = {
new T$$anon$1()
};
scala.this.Predef.assert(scala.Int.unbox({
val qual1: java.lang.Object = e;
{
var exceptionResult1: java.lang.Object = _;
try {
exceptionResult1 = T.reflMethod$Method1(qual1.getClass()).invoke(qual1, Array[java.lang.Object]{})
} catch {
case ($1$ @ (_: java.lang.reflect.InvocationTargetException)) => {
exceptionResult1 = throw $1$.getCause()
}
};
exceptionResult1
}.$asInstanceOf[java.lang.Integer]()
}).==(5))
};
def this(): object T = {
T.reflParams$Cache1 = Array[java.lang.Class]{};
T.reflPoly$Cache1 = new scala.runtime.EmptyMethodCache();
T.super.this();
()
}
};
final class T$$anon$1 extends java.lang.Object {
private[this] var id: Int = _;
<accessor> def id(): Int = T$$anon$1.this.id;
<accessor> def id_=(x$1: Int): Unit = T$$anon$1.this.id = x$1;
private[this] var name: java.lang.String = _;
<accessor> def name(): java.lang.String = T$$anon$1.this.name;
<accessor> def name_=(x$1: java.lang.String): Unit = T$$anon$1.this.name = x$1;
def this(): T$$anon$1 = {
T$$anon$1.super.this();
T$$anon$1.this.id = 5;
T$$anon$1.this.name = "Prashant";
()
}
}
}
关于c# - 有没有办法在 Scala 中使用命名字段的元组,类似于 C# 中的匿名类?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1827672/