php - 填补多维数组中的空白

Question

我有一个来自这个 mysql 查询的数组:

SELECT COUNT(*) as opens, HOUR(FROM_UNIXTIME(open_date)) as hour 
FROM tracking WHERE open_id = 10 GROUP BY HOUR(FROM_UNIXTIME(open_date)) 

它让我可以根据每小时获得打开。但是，由于在特定时间没有打开任何东西，因此时间存在一些差距。我怎样才能填补空白，即转动这个数组:

Array ( 
[0] => Array ( [opens] => 9 [hour] => 0 ) 
[1] => Array ( [opens] => 2 [hour] => 3 ) )

进入:

Array ( 
[0] => Array ( [opens] => 9 [hour] => 0 ) 
[1] => Array ( [opens] => 0 [hour] => 1 ) 
[2] => Array ( [opens] => 0 [hour] => 2 ) 
[3] => Array ( [opens] => 2 [hour] => 3 ) )

换句话说，用 0 个打开来填补缺失的时间？我可以更改我的 sql 查询以使其正常工作还是必须通过 PHP？

感谢大家的帮助。

Answer 1

$aHours = array();

foreach (range(0,23) as $nHour){

    $aHours[] = array('opens' => 0, 'hour' => $nHour);

}

// your query goes here with result into $aMyQueryResult

foreach ($aMyQueryResult as $aOpensHour){

  $aHours[$aOpensHour['hour']] = $aOpensHour;

}