我花了几个小时阅读并试图找出为什么这不起作用但下拉菜单没有填充。我认为这很简单,但我就是看不到。有人吗?
数据库连接器
<?php
define('DB_NAME' , 'artprints');
define('DB_USER' , 'root');
define('DB_PASS' , '');
define('DB_HOST' , 'localhost');
函数.php
<?php
include_once 'dbconn.php';
function connect(){
$connection = mysqli_connect(DB_HOST, DB_USER, DB_PASS) or die ('Could not connect to the database' . mysl_error());
mysqli_select_db($connection, DB_NAME);
}
function close(){
mysql_close();
}
function query(){
$myData = mysql_query("SELECT * FROM artists");
while ($record = mysql_fetch_array($myData)){
echo '<option value="' . $record['artistID'] . '">' . $record['artistID'] . '</option>';
}
}
测试.php
<?php
include_once 'func.php';
connect();
?>
<html>
<head>
<title>Drop down testing</title>
</head>
<body>
<select name='artist'>
<?php query() ?>
</select>
<?php close() ?>
</body>
</html>
最佳答案
你正在混合使用 mysqli_*
和 mysql_*
mysqli_connect
和 mysqli_select_db
反对
mysql_query
和 mysql_fetch_array
关于从mysql填充的PHP下拉菜单不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19978763/