我有一个如下所示的数据库表:
id | macaddr | load | timestamp
=========================================
1 | 0011111 | 17 | 2012-02-07 10:00:00
1 | 0011111 | 6 | 2012-02-07 12:00:00
2 | 0022222 | 3 | 2012-02-07 12:00:03
3 | 0033333 | 9 | 2012-02-07 12:00:04
4 | 0022222 | 4 | 2012-02-07 12:00:06
5 | 0033333 | 8 | 2012-02-07 12:00:10
...
现在,我想计算不同时间段内所有设备(= mac 地址)的平均负载,例如,今天、昨天、本周、本月。
可以通过首先找出不同时间点(样本日期)的总负荷总和,然后计算这些样本日期的负荷总和的平均值来计算平均负荷。例如,如果我想要最后十秒的平均负载(现在是 2012-02-07 12:00:10),我可以将样本日期定在 12:00:02、12:00: 04、12:00:06、12:00:08 和 12:00:10。然后,我将通过汇总每个设备的最新负载值来计算负载总和:
2012-02-07 12:00:02 | 6 [= load(id=2)]
2012-02-07 12:00:04 | 18 [= load(id=2) + load(id=3) + load(id=4)]
2012-02-07 12:00:06 | 19 [= load(id=2) + load(id=4) + load(id=5)]
2012-02-07 12:00:08 | 19 [= load(id=2) + load(id=4) + load(id=5)]
2012-02-07 12:00:10 | 18 [= load(id=2) + load(id=5) + load(id=6)]
如果设备的负载值早于例如一个小时(此处发生 id=1),则该设备的负载值将被忽略。在这种情况下,平均值为 16。
目前,我生成了一个相当复杂的查询,其中包含许多“UNION ALL”语句,速度非常慢:
SELECT avg(l.load_sum) as avg_load
FROM (
SELECT sum(so.load) AS load_sum
FROM (
SELECT *
FROM (
SELECT si.macaddr, si.load
FROM sensor_data si WHERE si.timestamp > '2012-02-07 11:00:10' AND si.timestamp < '2012-02-07 12:00:10'
ORDER BY si.timestamp DESC
) AS sm
GROUP BY macaddr
) so
UNION ALL
[THE SAME THING AGAIN WITH OTHER TIMESTAMPS]
UNION ALL
[AND AGAIN]
UNION ALL
[AND AGAIN]
...
) l
现在假设我想计算整个月的平均负载。对于每小时采样日期,我需要使用 UNION ALL 语句加入 30x24=720 个查询。在我的机器上完成整个查询需要将近一分钟。我确信没有 UNION ALL 语句会有更好的解决方案。但是,我没有在网上找到任何有用的东西。因此,非常感谢您的帮助!
最佳答案
使用 unix 时间戳的一小部分:首先我们计算每小时(3600 秒)的平均值:
SELECT
macaddr,
sum(CAST(load AS float))/CAST(count(*) AS float) AS loadavg,
FLOOR(UNIX_TIMESTAMP(`timestamp`)/3600) AS hourbase
FROM sensor_data
GROUP BY macaddr,FLOOR(UNIX_TIMESTAMP(`timestamp`)/3600)
然后我们计算一个月的平均值
SELECT
avg(loadavg) as monthlyavg,
macaddr
FROM (
SELECT
macaddr,
sum(CAST(load AS float))/CAST(count(*) AS float) AS loadavg,
FLOOR(UNIX_TIMESTAMP(`timestamp`)/3600) AS hourbase
FROM sensor_data
WHERE `timestamp` BETWEEN '2012-01-07 12:00:00' AND '2012-02-07 11:59:59'
GROUP BY macaddr,FLOOR(UNIX_TIMESTAMP(`timestamp`)/3600)
) AS hourlies
GROUP BY macaddr, hourbase
关于mysql - 如何有效地选择基于 SQL 中不同时间戳计算的多个总和的平均总和?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9184535/