php - 按用户跟踪/验证/更新 MySQL 结果

Question

我有一个时间表数据库，志愿者可以在其中查看他们的类次。我将通过电子邮件向他们发送一个链接，指向他们将电子邮件地址输入到 HTML 表单中以访问此信息的页面。

有没有一种方法可以跟踪查询了哪些电子邮件，以便我可以将计划链接重新发送给那些没有访问过数据库的人？

如有必要，我可以在结果中添加一个额外的“已确认”复选框，并更新数据库。我喜欢这个想法，但我不确定如何实现(或该操作的术语)。

编辑:这是我用来实现的代码。但是我没有在 confirmed 列中得到结果。

                $db = new mysqli("host", "user", "pass", "db");

    $stmt = $db->prepare('UPDATE volConfirm SET confirmed = TRUE WHERE email = ?');
    $stmt->bind_param('s', $_POST['email']);
    $stmt->execute();

    $stmt = $db->prepare('SELECT * from volConfirm WHERE email = ?');
    $stmt->bind_param('s', $_POST['email']);
    $result = $stmt->get_result();
    while ($row = $result->fetch_array(MYSQLI_NUM)) {
    // construct your output here using $row to access database record
    echo "<h2>" . $row['agreeName'] . "</h2>";
    echo "<p> You have been assigned as a volunteer for:" . $row['position'] . "</p>";
    echo "<p>Your shift times are scheduled for:" . $row['shift_times'] . "</p>";
    echo "<p>Your shift has been confirmed:" . $row['confirmed'] . "</p>";
    }

Answer 1

您需要按照以下方式做一些事情:

1. 在您的志愿者表中添加一个新列

   ALTER TABLE Volunteers ADD COLUMN Confirmed BOOLEAN NOT NULL DEFAULT FALSE;
   

2. 让提交页面中的 PHP 更新该列:

   UPDATE Volunteers SET Confirmed = TRUE WHERE Email = 'foo@bar.com';
   

   在您的代码片段中:

   $db = new mysqli("dbhostname", "username", "password", "dbschema");
   
   $stmt = $db->prepare('UPDATE volConfirm SET confirmed = TRUE WHERE email = ?');
   $stmt->bind_param('s', $_POST['email']);
   $stmt->execute();
   
   $stmt = $db->prepare('SELECT * from volConfirm WHERE email = ?');
   $stmt->bind_param('s', $_POST['email']);
   $result = $stmt->get_result();
   
   while ($row = $result->fetch_array(MYSQLI_NUM)) {
     // construct your output here using $row to access database record
   }
   

3. 在未来的某个时刻，获取尚未访问该页面的所有用户的列表:

   SELECT Email FROM Volunteers WHERE Confirmed = FALSE;