我的数据库字段没有填充,但页面确认它存在。所以第一个 SQL 正在运行,但第二个没有提取信息。如果我把页面 checkout 。它找不到页面并重定向到 page_not_found。我这样做正确吗?我在这里做错了什么?
//get page url and query db
$this_page = $_GET['page'];
$this_page = escape_data($_GET['page']);
//Make sure page exist
$SQL_page_exist = "SELECT page_title FROM learn_more WHERE page_title = '$this_page'";
$SPE_result = mysql_query($SQL_page_exist);
if(mysql_num_rows($SPE_result) == 0)
{
echo '<META HTTP-EQUIV="Refresh" Content="0; URL=page_not_found.php">';
}
else {
$SQL =
"SELECT * FROM learn_more AS lm
INNER JOIN learn_more_to_reference_key AS lmtrk
ON lm.id = lmtrk.learn_more_id
INNER JOIN reference_keys AS rk
ON rk.keys_id = lmtrk.reference_key_id
WHERE page_title = '$this_page'";
$result = mysql_query($SQL);
while ($db_field = mysql_fetch_assoc($result));
{
$id = $db_field['ID'];
$main_title = $db_field['main_title'];
$main_content = $db_field['main_content'];
$reference_keys = $db_field['keys_href'];
$sub_title = $db_field['sub_title'];
$sub_content = $db_field['sub_content'];
}
}
mysql_close($dbc);
最佳答案
您应该删除 while 语句后的分号,因为它不会执行以下附件(意味着您的查询没问题,但 while 语句无效)。
此外,我不确定,但声明:
$id = $db_field['ID'];
如果 mysql 字段是“id”(小写),可能会产生错误。虽然 MySQL(通常)不区分大小写,但 php 数组键却区分大小写,因此该键可能仅可用作“id”而不是“ID”...
关于PHP 没有错误显示但没有获取数据库字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11440211/