我的查询是
select COUNT(*) from result
where test_id in (select test_id
from test_schedule
where scheduler_id in (select user_id
from users
where user_type=1))
最佳答案
试试这个:
SELECT COUNT(r.*)
FROM result r
INNER JOIN test_schedule s ON r.test_id = s.test_id
INNER JOIN users u ON s.scheduler_id = u.user_id
WHERE u.user_type = 1
关于mysql - 将嵌套选择转换为连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13134540/