我正在尝试制作一个星级评分系统，但我无法将结果插入到 mysql 中。我错过了一些东西，但我不知道是什么。我将向您展示我的代码，也许你们中的一个可以看出问题出在哪里。 提前致谢!
首先，我的表格:
<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' 'http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<script src='jquery.js' type="text/javascript"></script>
<script src='documentation/documentation.js' type="text/javascript"></script>
<link href='documentation/documentation.css' type="text/css" rel="stylesheet"/>
<script type="text/javaScript" src="documentation/chili/jquery.chili-2.0.js"></script>
<script type="text/javascript">try{ChiliBook.recipeFolder="documentation/chili/"}catch(e){}</script>
<script src='jquery.MetaData.js' type="text/javascript" language="javascript"></script>
<script src='jquery.rating.js' type="text/javascript" language="javascript"></script>
<link href='jquery.rating.css' type="text/css" rel="stylesheet"/>
</head>
<body>
<div id="tab-Testing">
<script>
$('form1').submit(function() {
var ans=$(this).serialize();
$.ajax({
type: "POST",
url: "starsubmit.php",
data:ans
}).done(function( msg ) {
alert( "Data Saved: " + msg );
});
return false;
});
</script>
<div class="Clear"> </div>
<form id="form1">
Question 1:bla bla bla
<input class="star required" type="radio" name="Question 1" value="1"/>
<input class="star" type="radio" name="Question 1" value="2"/>
<input class="star" type="radio" name="Question 1" value="3"/>
<input class="star" type="radio" name="Question 1" value="4"/>
<input class="star" type="radio" name="Question 1" value="5"/>
</div>
<br/>
<div class="Clear">
Question 2:bla bla bla
<input class="star required" type="radio" name="Question 2" value="1"/>
<input class="star" type="radio" name="Question 2" value="2"/>
<input class="star" type="radio" name="Question 2" value="3"/>
<input class="star" type="radio" name="Question 2" value="4"/>
<input class="star" type="radio" name="Question 2" value="5"/>
</div>
<br/>
<div class="Clear">
Question 3:bla bla bla
<input class="star required" type="radio" name="Question 3" value="1"/>
<input class="star" type="radio" name="Question 3" value="2"/>
<input class="star" type="radio" name="Question 3" value="3"/>
<input class="star" type="radio" name="Question 3" value="4"/>
<input class="star" type="radio" name="Question 3" value="5"/>
</div>
<br>
<div class="Clear">
Question 4:bla bla bla
<input class="star required" type="radio" name="Question 4" value="1" />
<input class="star" type="radio" name="Question 4" value="2" />
<input class="star" type="radio" name="Question 4" value="3" />
<input class="star" type="radio" name="Question 4" value="4" />
<input class="star" type="radio" name="Question 4" value="5" />
</div>
<br/>
<div class="Clear">
Question 5:bla bla bla
<input class="star required" type="radio" name="Question 5" value="1"/>
<input class="star" type="radio" name="Question 5" value="2"/>
<input class="star" type="radio" name="Question 5" value="3"/>
<input class="star" type="radio" name="Question 5" value="4"/>
<input class="star" type="radio" name="Question 5" value="5"/>
</div>
<br/>
<div class="Clear">
Question 6:bla bla bla
<input class="star required" type="radio" name="Question 6" value="1" />
<input class="star" type="radio" name="Question 6" value="2" />
<input class="star" type="radio" name="Question 6" value="3" />
<input class="star" type="radio" name="Question 6" value="4" />
<input class="star" type="radio" name="Question 6" value="5" />
</div>
<input type="submit" value="Submit scores!" /> </td>
</form>
</body>
</html>
Now, my starsubmit.php:
<?php
$mysql_hostname = "localhost";
$mysql_user = "root";
$mysql_password = "";
$mysql_database = "cosmote";
$prefix = "";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Opps some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Opps some thing went wrong");
if($_SERVER["REQUEST_METHOD"] == "POST")
{
$question1 = mysql_real_escape_string($_POST['question1']);
$question2 = mysql_real_escape_string($_POST['question2']);
$question3 = mysql_real_escape_string($_POST['question3']);
$question4 = mysql_real_escape_string($_POST['question4']);
$question5 = mysql_real_escape_string($_POST['question5']);
$question6 = mysql_real_escape_string($_POST['question6']);
mysql_query("INSERT INTO answers (q1,q2,q3,q4,q5,q6) VALUES ('$question1','$question2','$question3','$question4','$question5','$question6')");
echo "<h1>Thank You !</h1>";
}
?>
最后，我的 table :
CREATE TABLE IF NOT EXISTS `answers` (
`q1` int(3) NOT NULL,
`q2` int(3) NOT NULL,
`q3` int(3) NOT NULL,
`q4` int(3) NOT NULL,
`q5` int(3) NOT NULL,
`q6` int(3) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
最佳答案
我必须说这应该是:
$('form1').submit(function() { // <------you are not submiting the specific form
像这样:
$('#form1').submit(function() { // <------ every id should have a '#' in jquery
如果您可以更改 .done 函数，这可能就是问题所在
.done(function() {
alert( "Data Saved"); // try removing the passed param "msg"
});
关于PHP、Mysql插入，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13430027/