mysql - 选择最具体的连接结果

Question

我正在尝试让 mysql 返回商店商品的最具体折扣，因为可能有多个折扣适用。我的表格和数据如下(不相关的列已被省略):

Item
  itemId   brand    supplier   price
  ======   =====    ========   =====
  Item1    Brand1   Supply1    100
  Item2    Brand2   Supply1    100
  Item3    Brand3   Supply1    100
  Item4    Brand4   Supply2    100

Discount
  discountId   itemId   brand    supplier   discountPrice
  ==========   ======   ======   ========   =============
  Discount1    (null)   (null)   Supply1    80
  Discount2    (null)   Brand2   Supply1    60
  Discount3    Item3    (null)   (null)     40

我期望的查询输出是

itemId  price  discountPrice
===================================
Item1   100    80
Item2   100    60
Item3   100    40
Item4   100    (null)

如你所见，我的规则是

1. 供应商折扣最不明确
2. 供应商+品牌折扣更具体
3. ItemId 折扣最具体

然而，在子句上使用 or 进行正常的左连接将返回所有组合，而不是最具体的折扣。我怎样才能做到这一点？

选择 item.itemId, item.price, discount.discountPrice from item left join discount on (item.itemId = discount.itemId) or (item.brand = discount.brand and item.supplier = discount.supplier ) 或 (item.supplier = discount.supplier AND discount.brand IS NULL)

Answer 1

查询:

SQLFIDDLEEXample

SELECT i.itemId, 
       i.price, 
       COALESCE(d.discountPrice, d2.discountPrice, d3.discountPrice) AS discountPrice 
FROM item i
LEFT JOIN discount d 
  ON i.itemId = d.itemId
LEFT JOIN discount d2
  ON i.brand = d2.brand
  AND i.supplier = d2.supplier 
LEFT JOIN discount d3
 ON i.supplier = d3.supplier 
 AND d3.brand IS NULL

结果:

| ITEMID | PRICE | DISCOUNTPRICE |
----------------------------------
|  Item1 |   100 |            80 |
|  Item2 |   100 |            60 |
|  Item3 |   100 |            40 |
|  Item4 |   100 |        (null) |