SELECT
bp.project_id,
bp.project_name,
bp.project_costing,
bp.project_borrower_id,
bp.member_userid,
bp.project_staus,
SUM(pb.payment_amount) as total
FROM borrower_project_master as bp
INNER JOIN payment_invest_master as pb ON bp.project_borrower_id=pb.payment_borrowerid
WHERE (
(SUM(pb.payment_amount)/bp.project_costing)*100 < 100
AND bp.project_staus='Y'
)
ORDER BY RAND() LIMIT 0,3
此查询显示错误组函数的使用无效。你能帮我解决这个问题吗
最佳答案
只需将 JOIN 表替换为计算每个 payment_borrowerid
总和的子查询
SELECT bp.project_id,bp.project_name,bp.project_costing,bp.project_borrower_id,
bp.member_userid,bp.project_staus,pb.SUM_payment_amount as total
FROM borrower_project_master as bp
INNER JOIN
( select payment_borrowerid,SUM(payment_amount) as SUM_payment_amount
FROM
payment_invest_master
GROUP BY payment_borrowerid
)
as pb ON bp.project_borrower_id=pb.payment_borrowerid
WHERE (
(pb.SUM_payment_amount/bp.project_costing)*100 < 100
AND bp.project_staus='Y'
)
ORDER BY RAND() LIMIT 0,3
关于php - mysql错误内连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19722576/