我很难弄清楚所有事情，这个问题来自这个问题，Inserting into a Table joined to another Table by a reference table? .
好吧，这个问题中解释了我想做的一半事情，我想做的其他一些事情将在这个问题中解释。
我在 Teams 表(也可以是 Projects 表)和 Members 表中有这些数据
+---------+---------------------+----------------------+
| team_id | team_name | team_desc |
+---------+---------------------+----------------------+
| 1 | Toronto Maple Leafs | Team is Awesome! |
| 2 | Vancouver Kanucks | Team Sucks! |
| 3 | Chicago Bulls | Team is Fine! |
| 4 | New York Boys | Nah! It doesn't suck |
+---------+---------------------+----------------------+
Members 表中的数据
+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+
| member_id | firstname | lastname | address | state | country | email | phone | experience | designation | username | password |
+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+
| 1 | Duncan | Daniel | P.O. Box 470, 2775 Ac Road | NS | Israel | duncan@aol.in | 9288091790 | 1 | Script | duncan | debbyisaweseome |
| 2 | Ivan | Richmond | P.O. Box 797, 906 Cursus Street | New Brunswick | Timor-Leste | ligula.tortor.dictum@Duis.com | 8087179788 | 5 | Storyboard | ivan | ivaniscool |
+-----------+-----------+----------+---------------------------------+---------------+-------------+-------------------------------+------------+------------+-------------+----------+-----------------+
这两个表由这个 teams_members 表连接，
+------------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------------+---------+------+-----+---------+----------------+
| teams_members_id | int(11) | NO | PRI | NULL | auto_increment |
| teams_id | int(11) | NO | MUL | NULL | |
| members_id | int(11) | NO | MUL | NULL | |
+------------------+---------+------+-----+---------+----------------+
如您所见，teams_id 和 members_id 是来自团队和成员的外键。
现在按照提到的问题中的 upvoted 帖子中的建议，我首先将一行插入团队，然后像这样插入 team_members 表，
INSERT INTO teams(`team_name`,`team_desc`) values ("New York Boys", "Nah! It doesn't suck");
INSERT INTO teams_members (`members_id`,`teams_id`) VALUES
((SELECT member_id from members WHERE member_id = 2),
(SELECT team_id from teams WHERE team_name = "New York Boys"))
然后像这样尝试为特定成员创建的团队进行选择，
SELECT * FROM teams_members, members, teams WHERE members_id = member_id && member_id = 1;
但它没有只显示一个团队，而是给了我这个结果:
+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+
| teams_members_id | teams_id | members_id | member_id | firstname | lastname | address | state | country | email | phone | experience | designation | username | password | team_id | team_name | team_desc |
+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+
| 1 | 3 | 1 | 1 | Duncan | Daniel | P.O. Box 470, 2775 Ac Road | NS | Israel | duncan@aol.in | 9288091790 | 1 | Script | duncan | debbyisaweseome | 1 | Toronto Maple Leafs | Team is Awesome! |
| 1 | 3 | 1 | 1 | Duncan | Daniel | P.O. Box 470, 2775 Ac Road | NS | Israel | duncan@aol.in | 9288091790 | 1 | Script | duncan | debbyisaweseome | 2 | Vancouver Kanucks | Team Sucks! |
| 1 | 3 | 1 | 1 | Duncan | Daniel | P.O. Box 470, 2775 Ac Road | NS | Israel | duncan@aol.in | 9288091790 | 1 | Script | duncan | debbyisaweseome | 3 | Chicago Bulls | Team is Fine! |
| 1 | 3 | 1 | 1 | Duncan | Daniel | P.O. Box 470, 2775 Ac Road | NS | Israel | duncan@aol.in | 9288091790 | 1 | Script | duncan | debbyisaweseome | 4 | New York Boys | Nah! It doesn't suck |
+------------------+----------+------------+-----------+-----------+----------+----------------------------+-------+---------+---------------+------------+------------+-------------+----------+-----------------+---------+---------------------+----------------------+
我的查询中是否遗漏了什么？此外，关于插入部分，有没有更好的方法来做到这一点？
最佳答案
SELECT *
FROM teams_members tm, members m, teams t
WHERE tm.members_id = m.member_id
AND m.member_id = 1
AND tm.teams_id = t.team_id
关于php - 从由引用表连接的两个表中选择？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20065105/