php - MySQL 选择具有两个 where 条件且计数大于 1 且具有相同列 ID 的行

Question

在此示例中，结果应为 conversation_id 165337:

这是我目前无法使用的 MySQL:

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id              
FROM xf_conversation_recipient
WHERE user_id = '4465'
AND user_id = '1'
HAVING COUNT(DISTINCT conversation_id) > 1
");

这是有效的答案和代码:

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient
WHERE user_id IN ('4465','1') 
GROUP BY conversation_id HAVING c > 1
");

Answer 1

然后试试这个:

SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient  
GROUP BY conversation_id HAVING c > 1;

在你的情况下:

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient
WHERE user_id IN ('4465','1') 
GROUP BY conversation_id HAVING c > 1
");