MYSQL计算行和组之间的时间作为 session

Question

我的数据是这样的；

datetime
2014-12-28 07:26:29
2014-12-28 07:25:29
2014-12-28 07:24:29
2014-12-28 07:23:30
2014-12-28 07:22:29
2014-12-28 00:19:49
2014-12-27 22:24:52 * end
2014-12-27 22:23:52
2014-12-27 22:22:52
2014-12-27 22:21:52
2014-12-27 22:20:52 * start

我希望输出是这样的；

datetime_start         datetime_end             duration_in_mins
2014-12-28 07:22:29    2014-12-28 07:26:29      4
2014-12-28 00:19:49    2014-12-28 00:19:49      1
2014-12-27 22:20:52    2014-12-27 22:24:52      4

因此，如果下一行比另一行晚 1 分钟，它仍被视为同一 session 的一部分。有任何想法吗？

Answer 1

这可能不完全正确，但按照这些思路应该可以工作......

DROP TABLE IF EXISTS my_table;

CREATE TABLE my_table
(datetime DATETIME NOT NULL PRIMARY KEY);


INSERT INTO my_table VALUES
('2014-12-28 07:26:29'),
('2014-12-28 07:25:29'),
('2014-12-28 07:24:29'),
('2014-12-28 07:23:30'),
('2014-12-28 07:22:29'),
('2014-12-28 00:19:49'),
('2014-12-27 22:24:52'),
('2014-12-27 22:23:52'),
('2014-12-27 22:22:52'),
('2014-12-27 22:21:52'),
('2014-12-27 22:20:52');

SELECT MIN(a.datetime) start
     , MAX(a.datetime) end
     , TIMEDIFF(MAX(a.datetime)+INTERVAL 1 MINUTE,MIN(a.datetime)) diff
  FROM
     ( SELECT x.* 
     , MAX(y.datetime) a
     , MAX(y.datetime) < x.datetime - INTERVAL 1 MINUTE session
  FROM my_table x 
  JOIN my_table y 
    ON y.datetime < x.datetime 
 GROUP
    BY x.datetime
     ) a
  JOIN (SELECT @session := 1) vars
GROUP BY CASE WHEN session = 1 THEN @session := @session + 1 ELSE @session := @session END;

+---------------------+---------------------+----------+
| start               | end                 | diff     |
+---------------------+---------------------+----------+
| 2014-12-27 22:21:52 | 2014-12-27 22:24:52 | 00:04:00 |
| 2014-12-28 00:19:49 | 2014-12-28 00:19:49 | 00:01:00 |
| 2014-12-28 07:22:29 | 2014-12-28 07:22:29 | 00:01:00 |
| 2014-12-28 07:23:30 | 2014-12-28 07:26:29 | 00:03:59 |
+---------------------+---------------------+----------+