我在一张 table 上有很多批处理。这些批处理通常出现一次,但可以重复。我想获取具有最早创建日期(列)的特定产品代码(列)的每个批处理,带回与该批处理相关的其他字段(到期日、仓库等)。
到目前为止,我有以下查询:
SELECT DISTINCT lot_number, prod_code, date_received, expiry_date, quantity
FROM scheme.stquem
WHERE prod_code = '001'
AND lot_number != '' //removes blanks
ORDER BY lot_number
如何通过选择收到日期最早的批处理来删除重复项?
最佳答案
使用group by
和join
:
SELECT s.lot_number, s.prod_code, s.date_received, s.expiry_date, s.quantity
FROM scheme.stquem s JOIN
(SELECT lot_number, min(date_received) as mindr
FROM scheme.stquem
WHERE prod_code = '001' AND lot_number <> '' //removes blanks
GROUP BY lot_number
) sl
ON sl.lot_number = s.lot_number and sl.mindr = s.date_received
WHERE prod_code = '001'
ORDER BY s.lot_number;
关于mysql - SQL 查询返回列值的实例但返回其他字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30504390/