我有以下 3 个具有重复 ID 的表。我想从所有 3 个表中检索具有相同 ID 但具有不同名称和日期的记录。我需要查询以获得预期结果输出。
CREATE TABLE Student1
(`id` int,`status` int,`amount` int , `Name` varchar(10), `date` varchar(55))
;
INSERT INTO Student1
(`id`,`status`,`amount`, `Name`, `date`)
VALUES
(1,0,4500, 'ram', '04/02/2012'),
(2,0,2000, 'shyam', '05/09/2013'),
(4,0,1500, 'ghanshyam', '08/11/2014')
;
CREATE TABLE Student2
(`id` int,`status` int,`amount` int , `Name` varchar(10), `date` varchar(55))
;
INSERT INTO Student2
(`id`,`status`,`amount`, `Name`, `date`)
VALUES
(3,0,4500, 'gopal', '04/02/2012'),
(2,0,8000, 'radheshyam', '15/11/2013'),
(4,1,1500, 'ghanshyam', '18/10/2015')
;
CREATE TABLE Student3
(`id` int,`status` int,`amount` int , `Name` varchar(10), `date` varchar(55))
;
INSERT INTO Student3
(`id`,`status`,`amount`, `Name`, `date`)
VALUES
(1,1,4500, 'ram', '14/02/2012'),
(2,0,6500, 'radhe', '11/11/2014'),
(3,1,4500, 'gopal', '14/02/2015')
;
异常结果:
id status amount Name date
2 0 2000 shyam 05/09/2013
2 0 6500 radhe 11/11/2014
2 0 8000 radheshyam 15/11/2013
最佳答案
您只需使用union all
将表组合在一起。一种方法是:
select s.*
from (select s.* from student1 s union all
select s.* from student2 s union all
select s.* from student3 s
) s
where id = 2;
不过,正如我在评论中所说,通常您会拥有三个表而不是一个表。
我意识到我可能误解了这个问题。如果您想查找具有相同 ID 但名称不同的记录,请使用:
select s.id, group_concat(s.name) as names
from (select s.* from student1 s union all
select s.* from student2 s union all
select s.* from student3 s
) s
group by s.id
having count(distinct name) = 3 -- or perhaps >= 2, depending on what you mean
如果你想要完整的记录,你可以将它连接回原始表。
编辑:
如果你想要所有的原始行:
select s.*
from (select s.id, group_concat(s.name) as names
from (select s.* from student1 s union all
select s.* from student2 s union all
select s.* from student3 s
) s
group by s.id
having count(distinct name) = 3
) ss join
(select s.* from student1 s union all
select s.* from student2 s union all
select s.* from student3 s
) s
on ss.id = s.id;
关于mysql - 从 3 个表中选择具有不同列的 Common Record,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31357603/