我有以下查询:
SELECT name as String
, COUNT(*) Total
, SUM(product = 1) Product
FROM String
WHERE language = 1
GROUP
BY name
ORDER
BY total desc
LIMIT 10
此查询的目的是根据字符串在 String
表中的出现次数报告 TOP-10 字符串,并报告它们在特定产品(id = 1)中的出现次数。
我想在结果中添加另一列,用于计算每个字符串在另一个字符串中间出现的次数。为此,我有一个由全文索引索引的表 Copy
。
我的问题是弄清楚如何将 String
列的值从结果传递到此查询:
SELECT COUNT(name) as inAll
FROM Copy c
WHERE MATCH(c.name) AGAINST (/*String*/)
是否可以只通过一个SQL查询就达到这样的结果?
Before: After:
String Total Product String Total Product inAll
+-----+-----+------+ +-----+-----+-------+-----+
|blah | 52 | 12 | |blah | 52 | 12 | 96 |
|bleh | 23 | 14 | |bleh | 23 | 14 | 56 |
|bloh | 14 | 11 | |bloh | 14 | 11 | 34 |
+-----+-----+------+ +-----+-----+-------+-----+
谢谢。
编辑
我的模式:
CREATE TABLE Language (
`id` INT NOT NULL AUTO_INCREMENT,
`name` VARCHAR(30) NOT NULL,
`code` VARCHAR(10) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB CHARSET=utf8 COLLATE utf8_unicode_ci;
CREATE TABLE Product (
`id` INT NOT NULL AUTO_INCREMENT,
`name` VARCHAR(100) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB CHARSET=utf8 COLLATE utf8_unicode_ci;
CREATE TABLE String (
`id` INT NOT NULL AUTO_INCREMENT,
`label` VARCHAR(200),
`name` TEXT(500) NOT NULL,
`language` INT NOT NULL,
`product` INT NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE utf8_unicode_ci;
CREATE TABLE Copy (
`id` INT NOT NULL,
`name` TEXT(500) NOT NULL,
PRIMARY KEY (`id`),
FULLTEXT(name)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE utf8_unicode_ci;
加上 INSERT
、DELETE
、UPDATE
触发器。
最佳答案
您可以尝试连接String
和Copy
表:
SELECT COUNT(*) AS inAll, t.String AS String, t.Total AS Total, t.Product AS Product
FROM Copy c
INNER JOIN
(
SELECT name AS String, COUNT(*) Total, SUM(product = 1) Product
FROM String
WHERE language = 1
GROUP BY name
ORDER BY COUNT(*) desc
LIMIT 10
) t
ON c.name = t.name
关于mysql - 将一个查询的结果传递给另一个查询,然后合并这两个查询的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31379972/