所以...这是我的代码:
$paymentType=$_POST["paymentType"]; // in the first two lines the $_POST data is copied into normal variables to make it easier to handle
$paymentMethod=$_POST["paymentMethod"];
$amount=$_POST["amount"];
$date=$_POST["date"];
$other=$_POST["other"];
$mysqlserver="localhost"; // in the next six lines the connection to the server is set up just like before and the database is chosen
$mysqlusername="jakedean";
$mysqlpassword="jakedean";
$link=mysql_connect($mysqlserver, $mysqlusername, $mysqlpassword) or die ("Error connecting to mysql server: ".mysql_error());
$dbname = 'jakedean';
mysql_select_db($dbname, $link) or die ("Error selecting specified database on mysql server: ".mysql_error());
// the query which inserts the new data (from the variables) is set up and run
$addPaymentquery="INSERT INTO TBL_payments
(paymentType, paymentMethod, amount, date, other)
VALUES
('$paymentType', '$paymentMethod', '$amount', '$date', '$other')";
mysql_query($addPaymentquery) or die("Query to insert new Payment into TBL_payments failed with this error: ".mysql_error());
echo "<p class=\"thicker2\">You added a new Payment to Person ID:$personId! The Payment information added was:</p><p class=\"bold\">Payment Type:</p> <p class=\"thicker\">$paymentType</p>
<p class=\"bold\">Payment Method:</p> <p class=\"thicker\">$paymentMethod</p><p class=\"bold\">Amount Paid:</p> <p class=\"thicker\">$amount</p><p class=\"bold\">Date of Payment:</p> <p class=\"thicker\">$date</p>
<p class=\"bold\">Additional Comments:</p> <p class=\"thicker\">$other</p>";
错误是未定义索引的组合和无法更新子行，因为我错误地关联了 sql 表...
错误信息:
我不知道这是否有帮助，但在我的数据库中，不同表中的一些字段具有相同的名称...
几天来我一直在尝试解决这个问题，但我无法弄清楚，这是我建立的第一个数据库!感谢任何回复!
最佳答案
undefined index 是因为您试图从数组中获取不存在的属性。
数据库错误(带有外键的错误)是因为您的 TBL_payments 必须与 TBL_people 相关 - 这意味着您必须设置 TBL_payments。personId 到您当前用户的id(登录的那个人或者这笔付款所属的那个人)。
更新:
而且，当然，不要使用已弃用的，正如评论中提到的那样!
关于php - INSERT INTO TBL_payments undefined index 和父子外键，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34087003/