MySQL - 从重复项中选择

Question

SELECT sample_number, date_sampled, date_completed, COUNT(*) c FROM tbl_sample GROUP BY sample_number HAVING c > 1

上面的查询为我提供了所有重复的样本编号，如下所示:-

'483662','0000-00-00 00:00:00','0000-00-00 00:00:00','2'
'493812','2011-10-14 00:00:00','2011-10-28 11:24:11','2'
'497558','1970-01-01 01:00:00','1970-01-01 01:00:00','2'

以样本编号 483662 为例:-

'483662','0000-00-00 00:00:00','0000-00-00 00:00:00'
'483662','2011-09-02 00:00:00','2011-10-04 09:39:31'

我需要扩展此查询并选择 date_completed 为“0000-00-00 00:00:00”或“1970-01-01 01:00:00”的所有重复样本编号

知道我该怎么做吗？

Answer 1

试试这个:

SELECT DISTINCT A.sample_number 
FROM tbl_sample A 
INNER JOIN (SELECT sample_number, COUNT(*) c 
            FROM tbl_sample 
            GROUP BY sample_number HAVING c > 1
           ) AS B ON A.sample_number = B.sample_number 
WHERE A.date_completed IN ('0000-00-00 00:00:00', '1970-01-01 01:00:00')