php - 应用程序错误 "SQLSTATE[42000]"

Question

我构建了 restful API 及其工作，但是当我尝试将参数传递给链接时，下面显示错误，尽管当我打印参数时结果是正确的!

详细信息

Type: PDOException

Code: 42000

Message: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where Journal_name like 'Abhinav%' AND is_reported=1' at line 1

File: ...path/index.php

Line: 15

and line 15 is "$stmt = $db->query($sql);"

index.php

<?php

// index.php 

require 'confing.php';
require 'Slim/Slim.php';
\Slim\Slim::registerAutoloader();
$app = new \Slim\Slim();

$app->get('/rout', function() use ($app) {
    $db =getDB();
        $title = $app->request()->params('title');
        // echo 'title ='. $tilte print the correct title name get it by link
    $sql = "SELECT J_name FROM J where where `J_name` like '".$title."%' AND is_reported=1;";
    $stmt = $db->query($sql); 
    $pre = $stmt->fetchAll(PDO::FETCH_OBJ);
        $sql2 = "SELECT P_Name FROM P where `P_Name` like '".$title."%' AND is_reported=1;";
    $stmt2 = $db->query($sql2); 
    $pre2 = $stmt2->fetchAll(PDO::FETCH_OBJ);
    echo json_encode($pre);
    echo json_encode($pre2);
});
$app->run();
?>

Answer 1

在错误的查询中使用两次 where condition。

$sql = "SELECT J_name FROM J where where `J_name` like '".$title."%' AND is_reported=1";

                             ^^^^^^^^^^^

删除一个where

应该是

$sql = "SELECT J_name FROM J where `J_name` like '".$title."%' AND is_reported=1";