我有一个简单的 1 页 web 应用程序，它主要使用 AJAX 来获取/发布，但是，当我尝试在我的一个端点上运行 SQL 时，它会抛出一个内部服务器错误，我想不出为什么，我测试了我在 PHPMyAdmin 中的 SQL 命令有效，我进行了测试以确保我的值被捕获，它们确实被捕获，所以我看不到问题，任何帮助都会很好，这是我的表格:
<!DOCTYPE html>
<html lang="">
<head>
<meta charset="UTF-8">
<title>Add a new album</title>
</head>
<body>
<p class="yeah">Add a new album</p>
<form action="http://localhost:8000/musicOnline/assets/scripts/php/create/new/" method="post" enctype="multipart/form-data">
<input type="text" placeholder="Artist Name" name="artist" required>
<input type="text" placeholder="Album Name" name="album" required>
<input type="text" placeholder="Genre" name="genre" required>
<input type="date" placeholder="Release Date" name="release" required>
<input type="text" placeholder="Record Label" name="recordLabel" required>
<input type="text" placeholder="enter a star rating (1 - 5)" name="rating">
<input type="submit" value="submit">
</form>
</body>
</html>
我的 AJAX 处理程序:
//forms that post, put, delete or get
$(document).on("submit", "form", function (e) {
e.preventDefault();
$this = $(this),
$data = $this.serializeArray(),
$method = $this.attr("method"),
$endpointURL = $this.attr("action");
$.ajax({
type: $method,
data: $data,
url: $endpointURL,
success: function (data) {
$("#content-lockup").html(data);
},
error: function (jqXHR, textStatus, errorThrown) {
console.log("error: " + textStatus + ", error thrown: " + errorThrown);
}
});
return false;
});
和端点代码(/assets/scripts/php/create/new/):
<?php
require "http://localhost:8000/musicOnline/assets/scripts/php/dbConn/index.php";
$artist = $_POST['artist'];
$album = $_POST['album'];
$genre = $_POST['genre'];
$release = $_POST['release'];
$rating = $_POST['rating'];
$recordLabel = $_POST['recordLabel'];
try {
//prepare our statement
$preparedQuery = $conn->prepare("insert into albums (artistName, albumName, genre, releaseDate, recordLabel, rating) values ('" . $artist . "', '" . $album . "', '" . $genre . "', '" . $release . "', '" . $recordLabel . "', '" . $rating . "')");
//execute the statement
if($preparedQuery->execute()) {
echo "success";
$conn = null;
} else {
echo "nope";
$conn = null;
}
} catch(PDOException $e) {
echo 'Error: ' . $e->getMessage();
}
?>
还有我的数据库连接:
<?php
session_start();
//setup variables
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dgc_music_online";
//instantiate our PDO connection to the DB
$conn = new PDO("mysql:host=$servername;dbname=$dbname;", $username, $password);
?>
以及输出的 console.log 的屏幕截图:
最佳答案
尝试更改您的端点代码以遵循本手册:http://php.net/manual/en/pdo.prepared-statements.php
//prepare our statement
$preparedQuery = $conn->prepare("insert into albums (artistName, albumName, genre, releaseDate, recordLabel, rating) values (?, ?, ?, ?, ?, ?)");
//execute the statement
if($preparedQuery->execute(array($artist, $album, $genre, $release, $recordLabel, $rating))) {
关于php - 发布到 SQL 的端点问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35736034/