限制最大值和最小值的MySQL查询

Question

我有下表:

    INSERT INTO `test_table` (`id`, `x`, `y`) VALUES (1, 0, 10), (2, 6, 10),
    (3, 9, 10), (4, 2, 9), (5, 4, 9), (6, 3, 8), (7, 7, 8), (8, 9, 8),
    (9, 0, 7), (10, 2, 7), (11, 5, 7), (12, 10, 7), (13, 2, 6), (14, 7, 6),
    (15, 0, 5), (16, 4, 5), (17, 9, 5), (18, 1, 4), (19, 3, 4), (20, 5, 4),
    (21, 10, 4), (22, 8, 3), (23, 3, 2), (24, 6, 2), (25, 2, 1), (26, 8, 1),
    (27, 0, 0), (28, 5, 0), (29, 6, 0), (30, 10, 0);

代表下图:

红色或粉红色单元格中的数字代表“id”，这些单元格的坐标是“x”和“y”。

我所要做的就是想出一个查询来显示所有单元格(只有红色单元格)，不包括灰色方 block 内的第 10 个单元格。

到目前为止我有这个:

    SELECT * FROM `test_table` WHERE
    x between 0 and 10 and
    x not between 2 and 8 and
    y between 0 and 10 and
    y not between 2 and 7
    order by id ASC
    LIMIT 30

想象网格在两个方向上都低于 0 并超过 10(图中未显示)；查询必须有太多的限制。无论如何，输出不是我想要的，因为它只给我角落里的单元格(绿色区域内的单元格):1、3、8、27 和 30

另一种方法是减去这个查询:

    SELECT * FROM `test_table` WHERE
    x between 2 and 8 and
    y between 2 and 7
    order by id ASC
    LIMIT 30

来自这个:

    SELECT * FROM `test_table` WHERE
    x between 0 and 10 and
    y between 0 and 10
    order by id ASC
    LIMIT 30

...但是又一次；我做不到:(

Answer 1

只需要排除x[2:8],y[2,7]即可。

试试这个:

SELECT * FROM `test_table` 
WHERE NOT(x between 2 and 8 AND y between 2 and 7);