我有三个表
1.tbl_tag
id int NOT NULL AI PK
name VARCHAR(50) NOT NULL
content
id name
1 lifestyle
2 store
3 car
4 luxury
5 classy
6 boy
7 girl
8 man
9 woman
10 strong
etc ...
2.tbl_media
id int NOT NULL AI PK
name VARCHAR(50) NOT NULL
content
id name
1 one
2 two
3 three
4 four
5 five
6 six
7 seven
8 eight
9 nine
10 ten
etc...
<强>3。 tbl_media_tag
id int NOT NULL AI PK
media_id int NOT NULL -> relationship with tbl_media
tag_id int NOT NULL -> relationship with tbl_tag
content
id media_id tag_id
1 1 4
2 1 3
3 4 3
4 5 2
5 6 8
6 4 4
7 8 7
8 7 4
9 7 3
10 6 2
11 8 4
12 8 3
etc...
我想用 LIMIT 获得最流行的标签(tag_id)组合,例如最流行的前十名标签组合
我想得到这样的结果
4, 7, 3 (75)
4, 8 (42)
1, 7, 9, 10 (28)
7, 8, 9 (10)
7, 2 (2)
最佳答案
SELECT *
FROM
(SELECT tag_sum,
COUNT(*) as tag_sum_count
FROM
(SELECT GROUP_CONCAT(DISTINCT tag_id
ORDER BY tag_id DESC
SEPARATOR ',') as tag_sum,
media_id
FROM tbl_media_tag mt
GROUP BY media_id) sub
GROUP BY tag_sum) sub2
ORDER BY tag_sum_count DESC
LIMIT 10
关于php - MySQL 获取最受欢迎的标签 ID 组合及其计数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36688782/