在我被钉在十字架上之前,我已经研究了一个星期,如果有人能提供帮助,我将不胜感激。我还阅读了该平台上所有关于 password_hash
和 password_verify
的文章,但是没有一个解决方案对我有用,从字符串长度和数据库长度等等,所以我决定发布我的问题。
我正在编写一个登录脚本,我使用了password_verify
;我刚刚学习了 PHP 的安全性,想改进我的代码。
每次我尝试登录,它都登录不上。
public function create() {
// Don't forget your SQL syntax and good habits:
// - INSERT INTO table (key, key) VALUES ('value', 'value')
// - single-quotes around all values
// - escape all values to prevent SQL injection
/* $sql = "INSERT INTO users (username, password, first_name, last_name)
VALUES( ?, ?, ?, ?)";*/
$sql = "INSERT INTO users (username, password, email, date_created)
VALUES( :username, :password, :email, :date_created)";
try {
// prepare sql and bind parameters
$core = ConnectionManager::getInstance();
$stmt = $core->con->prepare($sql);
/*$stmt = $db->prepare("INSERT INTO users (id, username, password, first_name, last_name)
VALUES (:id, :username, :password, :first_name, :last_name");*/
//$stmt->bindParam(':id', 1);
$username = $this->username;
$password = password_hash($this->password, PASSWORD_BCRYPT);
$email = $this->email;
$date_created = strftime("%Y-%m-%d %H:%M:%S", time());
/*$username = "boiy";
$password = password_hash("redrum", PASSWORD_BCRYPT);
$email = "bdboiy@gmail.com";
$date_created = strftime("%Y-%m-%d %H:%M:%S", time());*/
$stmt->bindParam(':username', $username, PDO::PARAM_STR);
$stmt->bindParam(':password', $password, PDO::PARAM_STR);
$stmt->bindParam(':email', $email, PDO::PARAM_STR);
$stmt->bindParam(':date_created', $date_created, PDO::PARAM_STR);
if($stmt->execute()) {
$this->id = $core->con->lastInsertId();
echo "New records created successfully";
return true;
} else {
return false;
}
} catch (PDOException $e) {
echo "Insert Error: " . $e->getMessage();
}
}
那就是创建一个新用户。它奏效了。
然后我尝试登录用户:
if($session->is_logged_in()) {redirect_to("admin.php");}
// Remember to give your form's submit tag a name="submit" attribute!
if (isset($_POST['submit'])) { // Form has been submitted.
$username = trim($_POST['username']);
$password = trim($_POST['password']);
$YRJWA = "YRJWA";
$string = "$2y$10$$YRJWA/EJQGkmqev6VlpteOXHwF6DeQWcU1x1uGqmOdY4CDK5.oJYi";
// Check database to see if username/password exist.
$found_user = User::authenticate($username, $string);
if ($found_user) {
//if (password_verify($password, $found_user->password)) {
$session->login($found_user);
log_action('Login', "{$found_user->username} logged in.");
redirect_to("admin.php");
//}
} else {
// username/password combo was not found in the database
$message = "Username/password combination incorrect.";
}
} else { // Form has not been submitted.
$username = "";
$password = "";
}
当我这样做时,它不起作用。
当我输入 password_verify
时,它不起作用,所以我将其注释掉,如上面的代码所示。
然后我创建了一个新页面并在那里测试了我的代码:
$YRJWA = "YRJWA";
$string = "$2y$10$$YRJWA/EJQGkmqev6VlpteOXHwF6DeQWcU1x1uGqmOdY4CDK5.oJYi";
//$string = 'redrum';
echo "<hr>";
$found_user = User::authenticate('boiy', $string);
print_r($found_user);
echo "<br>";
/*echo strlen($found_user->password);*/
/*echo utf8_encode($found_user->password);
echo utf8_decode($found_user->password);*/
echo "<br/>";
//echo substr($found_user->password, 0, 60);
var_dump($found_user->password);
echo "<br>";
if(password_verify('redrum', $found_user->password)) {
echo "Valid";
} else {
echo "Invalid";
}
ConnectionManager::close();
当我直接从数据库使用密码时,它返回正确的数据并打印“有效”。
当我删除评论并尝试“redum”时出现此错误
Notice: Trying to get property of non-object in C:\xampp\htdocs\WealthPlus\private\index.php on line 36 NULL
Notice: Trying to get property of non-object in C:\xampp\htdocs\WealthPlus\private\index.php on line 39 Invalid
public static function authenticate($username="", $password="") {
$sql = "SELECT username, password FROM users WHERE username = :username AND password = :password LIMIT 1";
try {
$core = ConnectionManager::getInstance();
$stmt = $core->con->prepare($sql, array(PDO::ATTR_CURSOR => PDO::CURSOR_FWDONLY));
$stmt->execute([':username' => $username, ':password' => $password]);
$stmt->setFetchMode(PDO::FETCH_CLASS, "User");
$users = $stmt->fetch();
//if (password_verify($password, $users->password)) {
return $users;
//}
//return !empty($users) ? array_shift($users) : false;
}catch (PDOException $e) {
echo "Error: " . $e->getMessage();
}
}
最佳答案
如果您保存的是散列密码,则无法通过密码查找。您需要做的是获取用户记录,然后使用 password_verify
验证密码.
你甚至有这样的代码被禁用了:
public static function authenticate($username, $password) {
try {
$core = ConnectionManager::getInstance();
$stmt = $core->con->prepare("SELECT password FROM users WHERE username = :username";, array(PDO::ATTR_CURSOR => PDO::CURSOR_FWDONLY));
$stmt->execute([ ':username' => $username ]);
$stmt->setFetchMode(PDO::FETCH_CLASS, "User");
$user = $stmt->fetch();
if (password_verify($password, $user['password'])) {
return $users;
}
} catch (PDOException $e) {
echo "Error: " . $e->getMessage();
return false;
}
}
请记住,对username
之类的内容添加UNIQUE
约束,您无需担心LIMIT 1
,因为这是不可能的得到两行。
关于php - Password_Hash、Mysql、SetFetchMode、Password_verify,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39736118/